<span>Answer:
We'll have to integrate the growth rate with respect to time, without forgetting the amount of area covered at the start.
A = 2010 + â« 8t1/2 dt (as t goes from 0 to 24)
A = 2010 + [(16/3) t3/2] (as t goes from 0 to 24)
A = 2010 + 627 = 2637 acres
We don't integrate the 2010 here because whatever effects of the passing of time have already taken place over that area. We just treat it as a constant and add it to the result of integration.</span>
Answer:
The awnser on edge is C)147
Step-by-step explanation:
Hope this helped
