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3 years ago

A workgroup of 5 workers produced 500 units of output in a certain month working 22 days (8 hours per day).

Business

1 answer:

Sedbober [7]3 years ago

5 0

Answer:

The question continues ; b) Suppose that in the next month, the same work group produced 600 units but there were only 20 workdays in the month. Using the same productivity measures as before, determine the productivity index using the prior month as a base.

Explanation:

given 5 workers produced 500units working 8hrs/day for 22days

We calculate the output unit for each per worker for a month, a day and an hr;

Monthly output unit = 500/5 = 100 = LPR = Productivity ratios

daily output unit = 500/ 5x22 = 4.545 = LPR

hourly output unit = 500/ 22x8x5 = 0.568 = LPR

similarly for 600units produced by the same number but in 20days

Monthly output unit = 600/5 = 120 = LPR = Productivity ratios

daily output unit = 600/ 5x20 = 6.0 = LPR

hourly output unit = 600/ 20x8x5 = 0.75 = LPR

To calculate their productivity index ;

LPI = 120/100 = 1.2 = Monthly output unit

LPI = 6.0/4.545 = 1.32 = daily output unit

LPI = 0.75/0.568 = 1.32 = hourly output unit

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Answer:

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Explanation:

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Solve the simultaneous equation <br>y+x=4<br>2y-x=5

beks73 [17]

Answer:

<h2>Value of X = 1</h2>

<h2>Value of y = 3</h2>

Solution,

Using substitution method,

y + x = 4

Move 'x' to the left hand side and change its sign:

y = 4 - x --------> equation (i)

Now,

2y - X = 5

putting the value of y from equation (i)

2( 4 - x ) - X = 5

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The difference sign (-) will be cancelled in both sides

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Hope this helps...

Good luck on your assignment...

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