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3 years ago

15

In Mr.Ford’s class, 3 out of 25 students are left-handed. Whick of the following is the percent of “lefties” in Mr. Ford’s class

?

2 answers:

Alecsey [184]3 years ago

8 0

Answer:

no

Step-by-step explanation:

patriot [66]3 years ago

8 0

Answer:

12%

Step-by-step explanation:

<h3> $\frac{3}{25} = \frac{12}{100} = 12%$ </h3>

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The average of your first 6 tests is 82. If your test average after your seventh test is an 80.5, what did you score on the seve

mart [117]

So average is of the first 6 tests is 82 well that means

(test1 + test2+ test3+ test4 + test5+test6)/6 = 82

so now let do some cross multiplliying

test1 + test2 + test3 + test 4 + test5 +test6 = 82*6

test1 + test2 + test3 + test 4 + test5 +test6 = 492

now lets see if we can find that 7th test score

(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5

So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute.

(492 + test7 )/7 = 80.5

test7 = (80.5*7)-492 = 71.5

7 0

3 years ago

Trigonometry, can anybody help??

WINSTONCH [101]

Answer:

angle B: 39

AC: 7.288

AB: 11.58

(note: you cut off the part about rounding so make sure that it's rounded correctly before you put in your answer)

Step-by-step explanation:

To solve this we will use SOH, CAH, TOA

we have the angle and the one opposite to it which means we can use either SOH or TOA

let's use TOA

tan(51)=(9/x)

x= 7.288

We can now use pahtagaryous theroem to solve for the hyptonouse

we have

9²+7.288²=C²

C=11.58

Finally, to find angle B we will recall that the angles of a triangle must add to 180.

51+90+a=180

a=39

5 0

3 years ago

Which set of angle measures could be the measures of the interior angles of a triangle? please help me

marishachu [46]

Answer:

B. 60-60-60

Step-by-step explanation:

The interior angles of a triangle must add up to 180 degrees. The only set of numbers adding up to 180 is choice B.

8 0

3 years ago

What is the value of -8+4-7+9-2+(-5)

dsp73

Answer:

-9

Step-by-step explanation:

-8+4-7+9-2+(-5)

-8+4-7+9-2-5

-8-7-2-5+4+9

-22+13

-9

6 0

3 years ago

Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1

svet-max [94.6K]

Answer:

a) 0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

b) 0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.0 ounces and a standard deviation of 1.1 ounces.

This means that $\mu = 8, \sigma = 1.1$

(a) If 5 potatoes are randomly selected, find the probability that the mean weight is less than 9.3 ounces?

$n = 5$ means that $s = \frac{1.1}{\sqrt{5}} = 0.4919$

This probability is the pvalue of Z when X = 9.3. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{9.3 - 8}{0.4919}$

$Z = 2.64$

$Z = 2.64$ has a pvalue of 0.9959

0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

(b) If 6 potatoes are randomly selected, find the probability that the mean weight is more than 9.0 ounces?

$n = 6$ means that $s = \frac{1.1}{\sqrt{6}} = 0.4491$

This probability is 1 subtracted by the pvalue of Z when X = 9. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{9 - 8}{0.4491}$

$Z = 2.23$

$Z = 2.23$ has a pvalue of 0.9871

1 - 0.9871 = 0.0129

0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

8 0

3 years ago