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lys-0071 [83]
3 years ago
6

Use the following test scores. Find the mean, median score, mode, and spread. Round to the nearest whole number. 100 96 58 95 60

95 69 88 71 95 85 93 91 78 78 85 86 98 87 100
Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0
To find the mean, or average, we have to add all of the data numbers up and then divide by how many numbers there are.  

100+96+58+95+60+95+69+88+71+95+85+93+91+78+78+85+86+98+87+100 = 1708

Now, because there are 20 numbers, we divide this number by 20.

1708/20 = 85.4  

However, you want your answer rounded to the nearest whole number, therefore, your mean would be 85 (we round down, because 0.4 is less than 1/2.)

Now, let's find the median,or the middle of the set of data.  The median is found if you put all of these numbers in order, and then cross off one  number from each end of the set, until you reach the middle.  However, because there is an even amount of numbers, when you reach the middle for this set of data, you have to find the median between the two middle numbers in the set.

Long story short, the median is 87.5.  However, again, you want your answer rounded to the nearest whole number, which would be 88.

Now, for the mode, or the number that is repeated most in the data set.
The mode of this data set is 95, because it is repeated three times, the most out of all of the numbers.

So, in conclusion, 

Mean = 85

Median = 88

Mode = 95
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Answer:

The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = \overline{EF}/\overline{BC}

Step-by-step explanation:

From the question diagram, we have two triangles, ΔEAF and ΔABC;

The ratio of the lengths of the sides \overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC}

∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC

Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar

Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal

We have;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = 50 ft. /(100 ft.) =  \overline{EF}/\overline{BC} = \overline{EF}/120 ft.

\overline{EF} = 120 ft. × 50 ft./(100 ft.) = 60 ft.

\overline{EF} = 60 ft.

The distance between the pirate and the treasure, \overline{EF} = 60 ft.

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