Answer:
hu
Step-by-step explanation:
hij
Answer:
sec(B)=b. ab/bc
sin(B)=c. ac/ab
csc(B)=f. ab/ac
cot(B)=a. bc/ac
tan(B)=e. ac/bc
cos(B)=d. bc/ab
Step-by-step explanation:
<u><em>SOHCAHTOA</em></u>
<u><em>Sine=Opposite/Hypotenuse</em></u>
<u><em>Cosine=Adjacent/Hypotenuse</em></u>
<u><em>Tangent=Opposite/Adjacent</em></u>
<u><em>SHACHOCotAO</em></u>
<u><em>Secant=Hypotenuse/Adjacent</em></u>
<u><em>Cosecant=Hypotenuse/Opposite</em></u>
<u><em>Cotangent=Adjacent/Opposite</em></u>
<u><em /></u>
9514 1404 393
Answer:
{4, 5, 6, 7, 8}
Step-by-step explanation:
The inequality related to the perimeter is ...
x +(x +4) +11 < 32
2x < 17 . . . . . . . . . . . . subtract 15
x < 8.5
The inequality related to the triangle inequality is ...
(x) +(x +4) > 11
2x > 7
x > 3.5
Then possible whole-number values of x are ...
{4, 5, 6, 7, 8}
Answer:
x=2*root(41) or x=root(164)
Step-by-step explanation:
By using Pythagoras theorem, we have 8^2+10^2=x^2. 164=x^2, x=2*root(41)
Answer:
A. x = 8.
B. x = 31.
C. x = 32.
Step-by-step explanation:
Here. the sum of the 2 parallel sides of the trapezoid = 2 * length of the middle line segment.
MN + RS = 2PQ
32+ x = 2*20
x = 40 - 32
x = 8.
MN + RS = 2PQ
20 + 42 = 2PQ
2x = 62
x = 31
MN + RS = 2PQ
22 + 42 = 2PQ
2x = 64
x = 32.
