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sasho [114]
1 year ago
13

Help me please!!! i cant do these

Mathematics
1 answer:
LuckyWell [14K]1 year ago
6 0

Answer:

sec(B)=b. ab/bc

sin(B)=c. ac/ab

csc(B)=f. ab/ac

cot(B)=a. bc/ac

tan(B)=e. ac/bc

cos(B)=d. bc/ab

Step-by-step explanation:

<u><em>SOHCAHTOA</em></u>

<u><em>Sine=Opposite/Hypotenuse</em></u>

<u><em>Cosine=Adjacent/Hypotenuse</em></u>

<u><em>Tangent=Opposite/Adjacent</em></u>

<u><em>SHACHOCotAO</em></u>

<u><em>Secant=Hypotenuse/Adjacent</em></u>

<u><em>Cosecant=Hypotenuse/Opposite</em></u>

<u><em>Cotangent=Adjacent/Opposite</em></u>

<u><em /></u>

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Write the equation of the line perpendicular to F(x)=5 that goes through (-1, -3)
Ainat [17]

Answer:

x = -1

Step-by-step explanation:

y = 5 is a horizontal line

It's perpendicular would be a vertical line of the form:

x = a

Since it passes through (-1,-3)

a = -1

Hence line is: x = -1

3 0
2 years ago
What year is 40040040040049039qji34btuewrbgsnbbg snk g smart
raketka [301]
What? I don’t understand lol
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2 years ago
EASY 9th GRADE MATH PLEASE HELP
Harlamova29_29 [7]

Step-by-step explanation:

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5 0
2 years ago
Ví dụ 1.5. Một người đi mua hàng 3 lần. Xác suất lần đầu mua được hàng tốt là 0,7.
vodka [1.7K]

Answer:

a) 0.50575,

b) 0.042

Step-by-step explanation:

Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.

If the first time you can buy good products, the next time you can buy good products is 0.85;  (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).

And if the last time I bought a bad product, the next time I bought a good one is  0.6. Calculate the probability that:

a) All three times the person bought good goods.

P(Good on 1st shopping event AND Good on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) =

(0.7)(0.85)(0.85) =

0.50575      

b) Only the second time that person buys a bad product.

P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) =

(0.7)(1-0.85)(1-0.6) =

(0.7)(0.15)(0.4) =

0.042

5 0
2 years ago
CAN SOMEONE HELP ME WITH PATTERN 1
jeyben [28]
1- 6
2- 4
3- 2
And that’s all I can tell you? It’s decreasing so I don’t think 10 would have any stars unless if negative numbers are allowed
5 0
2 years ago
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