Point R is the midpoint of FE¯¯¯¯¯ , so the coordinates of point R are (3a, b).
In △DEF , the length of the base, DF¯¯¯¯¯ , is
4a, and the height is 2b, so its area is
1/2×4a×2b = 4ab.
In △QRP , the length of the base, QR¯¯¯¯¯ , is
3a-a = 2a, and the height is b, so its area is 1/2×2a×b = ab .
Comparing the expressions for the areas proves that the area of the triangle created by joining the midpoints of an isosceles triangle is one-fourth the area of the larger isosceles triangle.
Answer: 1/11 is the simplified form...
Hope this helps, stay safe :D
Answer:
8sm, 16sm, 10sm
Step-by-step explanation:
the first side of the triangle: x
the other side of the triangle: 2x
the third side of the triangle: x+2
the perimeter of the triangle: x+2x+x+2=34
4x=32
x=8
2*8=16
8+2=10
-11 divided by 4 and -11/4
Answer:
5 seconds
Step-by-step explanation:
hope it helps
correct me if i'm wrong
