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Cerrena [4.2K]
2 years ago
9

What is 1/5 + 3/10 ??

Mathematics
1 answer:
Anarel [89]2 years ago
7 0

Answer:

first we will make them like fractions

so 1/5= 2/10 so it will be

2/10+3/10= 5/10

HOPE IT HELPS

mark as brainliest

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Which of the following statements is true?
Ivahew [28]

The correct answer is C. A scalene triangle can be a right triangle.


This is because a scalene triangle is a triangle where all of the sides and angles are different from one another. This automatically tells us that options A and D are incorrect, because equiangular triangles have all 3 angles equivalent and if two sides were of equal length in the triangle, then it would not be scalene.


This leaves us with options B and C. An obtuse triangle simply has one angle with a measure greater than 90 degrees, and a right triangle is a triangle with a right angle (an angle that measures exactly 90 degrees). Scalene triangles can be both obtuse and right, as long as the side lengths and angles are not equal to one another. This makes option B incorrect, and option C the only correct option out of the four.


Your answer is option C.


Hope this helps!

7 0
3 years ago
Read 2 more answers
Estimate by rounding each addend to the greatest place: 50,099+ 24,565=74,664 .
Contact [7]
I'm not 100% sure what you're asking, but i think it wants:

50,000 + 25,000 = 75,000 - so B is the answer

to do it you basically just round the number to the nearest 1000 and add
8 0
3 years ago
A dilation by a factor of 7/8 maps triangle ABC to triangle XYZ. Segment BC has a length of 4 cm.
anastassius [24]
I believe the answer should be 3 and 1/2 which is 3.5 because I did the factor 7/8 times 4 and I got 3 and 1/2 I’m not sure
5 0
3 years ago
The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.
VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

\int\limits^2_{-1} {(f(x) - g(x))} \, dx

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx

We know that:

\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}

\int\limits^{}_{} {1} \, dx = x

\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}

Then our integral is:

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2}  + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3}  + (-1) - \frac{(-1)^2}{2}  )

The right side is equal to:

(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6

The bounded area is 5 + 5/6 square units.

3 0
2 years ago
The radius r of a circle can be written as a function of the area A with the following equation: r= sqrt(A/pi) What is the domai
Zepler [3.9K]
The domain of the function is \[A \ge0\] If A is negative we get an imaginary number for the radius. This makes sense because the area of a circle cannot be negative.
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