Answer:
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Step-by-step explanation:
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Answer:
16(n-1)
Step-by-step explanation:
16(n-1) is the simplest form of 16n-16 because you cannot backtrack any farther. To get to 16n-16, you must have 16(n-1) first. When you distribute, you will have 16n and -16. Put those into an equation, you get 16n-16 which is what you have originally.
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well, so the book is 180 and is discounted by 30%, how much will that be?
so from that discounted price, a tax of 4%
The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
Read more about binomial expansion at
brainly.com/question/13602562
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