3 years ago

What is the most hard subject in math

Mathematics

1 answer:

lesya692 [45]3 years ago

6 0

For me personally pre-calculus

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An airplane pilot is fertilizing a field. The height y in feet of the fertilizer t seconds after it is dropped is modeled by y(t

zheka24 [161]

Answer:

About 360.178 feet

Step-by-step explanation:

So we want the vertical distance between the fertilizer and the ground to be 0.

This going to be about the time the pilot has dropped it

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$0=-16t^2-3t+300$

We are going to use the quadratic formula to solve for t:

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The quadratic formula is:

$t=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$t=\frac{3 \pm \sqrt{(-3)^2-4(-16)(300)}}{2(-16)}$

$t=\frac{3 \pm \sqrt{9+19200}}{-32}$

$t=\frac{3 \pm \sqrt{19209}}{-32}$

$t=\frac{3+\sqrt{19209}}{-32} \text{ or } \frac{3-\sqrt{19209}}{-32}$

$t \approx -4.424891774 \text{ or } 4.237391774$

So the pilot has released it at about 4.237391774 seconds since the fertilizer has actually hit the ground at roughly this time.

So we want to know the horizontal distance at t=4.237391774:

$85t$

$85(4.237391774)$

$360.1783008$

360.178 feet

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Step-by-step explanation:

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