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mamaluj [8]
3 years ago
12

What type of energy transfer is occurring as the winds are moving?

Geography
2 answers:
Ne4ueva [31]3 years ago
5 0

Answer: Force

Explanation:

Nataly [62]3 years ago
4 0

Answer:

I believe it is conduction

Explanation:

Sorry if it was wrong!

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Kepler discovered that a planet does not orbit the Sun at a constant speed. Rather, at the point closest to the Sun known as the
BabaBlast [244]

Answer:

Fastest,

Explanation:

The farther a planet is away from the sun the slower it is, the closer it is the faster its orbit

6 0
3 years ago
A 215 kg rocket moving radially outward from Earth has a speed of 6.42 km/s when its engine shuts off 307 km above Earth's surfa
Vinvika [58]
<h2>GIVEN DATA</h2>

Mass of Rocket = m = 215 kg

Mass of Earth = M = 5.97*10^{24} kg

Radius of Earth = R = 6.37*10^6 m

Gravitational Constant = G = 6.67*10^-11 \;\;m^3kg^{-1}s^{-2}

Speed of Rocket = 6.42 km/s

Initial Height of Rocket from Earth's Surface = 307 km = 3.07*10^5 m

Final Height of Rocket from Earth's Surface = 731 km = 7.31*10^5 m

Initial Height from Earth's Centre = R_i = 3.07*10^5 + 6.37*10^6 = 6.677*10^6 m

Final Height from Earth's Surface = R_f = 7.31*10^5 + 6.37*10^6 = 7.101*10^6 m

(a) Kinetic Energy at Final Height = K.E_f

(b) Maximum Height of Rocket above Earth's Surface = H_{max}

<h2>EXPLANATION</h2>

Part (a):

As drag air is negligible, energy will be conserved.

\therefore ΔE = 0

K.E_i + U_i = K.E_f + U_f

K.E_f = U_f - K.E_i - U_i

where, U is the potential energy of the system.

K.E_f=\;G\frac{mM}{R_f} + \frac{1}{2}mv_i^2\;-\;G\frac{mM}{R_i}\;\;\;\;----------\;(1)

Substituting Values and simplifying,

K.E_f = 3.665*10^9 J

Part (b):

The rocket will come to rest after reaching the maximum height. Therefore, its final velocity and consequently final kinetic energy will be zero.

i.e.\;\;v_f = 0\;\;\;\&\;\;\; K.E_f=0

Equation (1) will become,

0\;=\;\;G\frac{mM}{R_f} + \frac{1}{2}mv_i^2\;-\;G\frac{mM}{R_i}

or\;\;\frac{1}{2}v_i^2= GM(\frac{1}{R_i}-\frac{1}{R_f})\\\\\frac{1}{2GM}v_i^2= (\frac{1}{R_i}-\frac{1}{R_f})\\\\\therefore\; R_f = \frac{2GMR_i}{2GM-v_i^2R_i}

Substituting values and simplifying,

R_f = 10.20*10^6 m

which is the distance from the Earth's centre. To find the height of rocket from Earth's surface, we simply subtract the Earth's radius from above result.

H_{max} = R_f - R

H_{max} = 10.20*10^6\;-\;6.37*10^6\\\\H_{max} = 3.83*10^6\;\;m

4 0
3 years ago
How far apart are the parallel lines?
PtichkaEL [24]

Answer:

69 miles/111 kilometers

Explanation:

The parallel lines, are lines that are parallel, as the name suggests. They at positioned north and south from the Equator, and they make east to west concentric circles around the planet.

These lines are imaginary, thus creating by humans, and the main purpose for it has been the measuring of latitude and measuring of exact location (in combination with the meridians).

These lines are approximately 69 miles, or 111 kilometers apart. Now this is a rough average, as there are slight differences because of the elliptical shape of Earth, but the differences are very small. The distance tends to be slightly less than the average on the lower latitudes, and slightly more on the high latitudes.

7 0
3 years ago
Wat would happen if both cold air masses had the same temperature
Elodia [21]
Ok, well assuming they had similar humidities,two similar air masses would just simply mix with no sensible effects caused by the mixing...
3 0
3 years ago
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Seawater is highly saline, which means it contains large amounts of dissolved salt. When seawater freezes and icebergs
Pachacha [2.7K]

Answer:

Because the amount of liquid water decreases and the amount of dissolved salt remains constant, the concentration of salt in the liquid water around the iceberg will increase.

Explanation:

7 0
3 years ago
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