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3 years ago

7

there was 135 buttons in a jar after Robin put more bottons into the jar there were 175 bottons in the jar how many groups of 10

bottons did she put into the jar

2 answers:

bulgar [2K]3 years ago

8 0

The correct answer is 4

lesya692 [45]3 years ago

6 0

13 if your staring from zero

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The table below represents the distance of a car from its destination as a function of time.

KIM [24]

We are given the table that projects the distance of the car per hour. x is associated to time while y is associated to distance. The equation of the line after plotting in MS Excel is y = 900 - 50x. Hence the y-intercept is equal to 900 while the slope is equal to -50. The domain of the function that is x is all positive numbers.

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3 years ago

What is 7.66666666667 in a simplified fraction?

KonstantinChe [14]

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6 0

3 years ago

Read 2 more answers

I need help with this problem if you can help please tell me what you did so I can understand please :)

balu736 [363]

The perimeter is 20 units

Step-by-step explanation:

The end-point of a side of square can be used to calculate length of a side. And the side will be used to calculate the perimeter.

Given

(3,-1) and (7,2)

Let

(3,-1) = (x1,y1)

(7,2) = (x2,y2)

We have to calculate the distance

The formula for distance is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let s be the side of a square

then,

$s=\sqrt{(7-3)^2+(2-(-1))^2}\\s=\sqrt{(4)^2+(2+1)^2}\\=\sqrt{16+(3)^2}\\=\sqrt{16+9}\\=\sqrt{25}\\=5\ units$

The side of square is 5 units. Then,

$Perimeter=P=4s\\=5*4\\=20\ units$

The perimeter is 20 units

Keywords: Perimeter, Square

Learn more about perimeter at:

#LearnwithBrainly

6 0

3 years ago

PLEASE ANSWER QUICKLY!!!!

nikitadnepr [17]

It’s kinda blurry, can u retake it

7 0

3 years ago

A local am radio station broadcasts at a frequency of 764 khz. calculate the energy of the frequency at which it is broadcasting

pentagon [3]

The frequency of the emitted radio waves is:
$f=764 kHz = 7.64 \cdot 10^5 Hz$

The energy of a photon is given by:
$E=hf$
where h is the Planck constant and f is the photon frequency. Using the frequency given by the problem, we can find the energy of each photon of this radiation:
$E=hf=(6.6 \cdot 10^{-34} Js)(7.64 \cdot 10^5 Hz)=5.04 \cdot 10^{-28} J=5.04 \cdot 10^{-31} kJ$

7 0

4 years ago