Answer:
I'm not SUPER sure but, it only can exist where there is a region in a planetary system where liquid water might exist on the surface of a planet. That puts it in the "habitable zone" which is where it can exist.
Answer:
A. 162 m²
Step-by-step explanation:
==>Given:
Isosceles trapezoid with:
base a = 19m
base b = 35m
Perimeter = 74meters
==>Required:
Area of trapezoid
==>Solution:
Recall: the length of the legs of an isosceles trapezoid are equal.
Perimeter of isosceles trapezoid = sum of the parallel sides + 2(length of a leg of the trapezoid)
Let l = leg of trapezoid.
Perimeter = 74m
Sum of parallel sides = a+b = 19+35 = 54m
Thus,
74 = 54 + 2(l)
74 - 54 = 2(l)
20 = 2(l)
l = 20/2 = 10m
Let's find area:
Area = ½(a+b)*h
a = 19
b = 35
h = ?
Using Pythagorean theorem, let's find h as follows:
h² = l² - [(35-19)/2)²
h² = 10² - [16/2]²
h² = 100 - 64
h² = 36
h = √36 = 6m
Area = ½ x (a+b) × h
= ½ × (19+35) × 6
= ½ × 54 × 6
= 27 × 6
Area = 162m²
Answer:
Step-by-step explanation:
The formula is given as:
We need to solve this formula for v, that means that v to one side and let it be solved in terms of the other variables (E and m). First, we isolate v:
To isolate v, and eliminate the "square", we need to take square roots of both sides, that will give us v in terms of the other variables:
Putting v to left side (convention), we finally have:
Answer:
9+15i
Step-by-step explanation:
This is a rhombus and in any rhombus, the diagonals intersects in the middle and they are perpendicular:
So all 4 triangles are right triangles and the sides are the hypotenuses.
1st) Calculate the sides: hypotenuse² = 3² + 4² = 25, and hypotenuse = 5
The area of each right triangle is (4 x 3)/2 = 6 units²
And the area of the 4 right triangles = 4 x 6 = 24 init²
