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erastovalidia [21]
2 years ago
7

Which statements are true about the experimental and theoretical probability of this trial?

Mathematics
2 answers:
uysha [10]2 years ago
9 0

Answer: A and B

Step-by-step explanation: becuse i just did it if you dont get it right report me

Licemer1 [7]2 years ago
4 0

Answer:

the correct answer is A and B

Step-by-step explanation:

i found this by guessing on the question and getting it correct. Also yeet leave five stars and and thanks if u are a swaglord with drip unknown to human kind.

You might be interested in
The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
2 years ago
(NECESITO PROCEDIMIENTO)<br> 9x + 8 = 7x + 6 <br><br> X= -1<br><br> X= 1/3<br><br> X= 1
Aloiza [94]

Answer:

x=-1

Step-by-step explanation:

9x+8=7x+6

Keep the variables in the left side & rest in the left side:

9x-7x=6-8

2x=-2

x=-2/2

x=-1

7 0
3 years ago
Add the following fractions. See the image below
LenKa [72]

Answer:

\dfrac{19}{840}

Step-by-step explanation:

The given fraction is:

\dfrac{1}{168}+\dfrac{3}{180}

We need to solve it.

The LCM of 168 and 180 is 2520.

So,

\dfrac{1}{168}+\dfrac{3}{180}=\dfrac{15+3\cdot14}{2520}\\\\=\dfrac{19}{840}

So, the required answer is equal to \dfrac{19}{840}.

3 0
2 years ago
6. Which is a unit rate?
Taya2010 [7]

it's A

Step-by-step explanation:

describes 55 per unit/the hour

3 0
3 years ago
Please help me with my math
Taya2010 [7]
3x + 22 is the equation that represents the perimeter of the triangle.  4x + 10 is the perimeter of the rectangle.  Setting the two equal:

3x + 22 = 4x + 10

and collecting like terms:

x=11

We find that the perimeter of both shapes is equal to 11 units.
8 0
3 years ago
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