Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.
Answer:
Step-by-step explanation:
To find (c.g)(x) we basically use the function d(x) as your variable, x, and plug it into c(x). So we replace every x in c(x) with the function d(x), 
c(g(x))=4(x^{2} +5x)-2
c(g(x))4
+20x-2
Answer:
Okk
Step-by-step explanation:
1.5x(-2-33)=5x-35=5(35:5)=5(x-7)
2.140+36=176/176-4x=4(44-x)
The area of that square would be 121 cm^2 because :
area of square = length(width)
= 11(11)
= 121
Then you also have to square the units(cm). So the final answer would be 121 cm^2 (the " ^ "represents the exponentiation)
