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IceJOKER [234]
3 years ago
15

How can I solve this problem

Mathematics
2 answers:
mart [117]3 years ago
7 0
I would say 36 and 49.
Alex Ar [27]3 years ago
4 0
36 and 49

6*6= 36
7*7= 49
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4 •f(6) - 6•g(5) =<br> please help me
Alborosie

Answer:

24f−30g

Step-by-step explanation:

4 0
3 years ago
The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
3 years ago
: Out of 100 students, 50 have a laptop computer and 30 have a desktop, and 15 have both a laptop and desktop computer. What is
Nadya [2.5K]

Answer:

30/100 I think but I think I am right.

6 0
3 years ago
How many edges does a regular prism have?​
Anton [14]

Answer:

12

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
At the local grocery store, cans of beans are arranged in rows. The number of cans in each row forms an arithmetic sequence. The
Elodia [21]
In an arithmetic series, the value of the nth term is calculated using the equation,
                                  an = ao + (n - 1)(d)
where an and ao are the nth and the 1st term, respectively. d is the common difference, and n is the number of terms.

In the given, an = 48, a0 = 93, d = -5 and n is unknown. Substituting the known values,
                                     48 = 93 + (n - 1)(-5)
The value of n from the equation is 10. Thus, the answer is the last choice. 
3 0
3 years ago
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