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lana [24]
3 years ago
6

Starting at 9 A.M. you hike for 3 hours at an average speed of 5 mph. You stop for lunch from noon until 3 P.M. What is your ave

rage speed over the interval from 9 A.M to 3 P.M.?
Physics
1 answer:
stellarik [79]3 years ago
4 0

Answer:

The average speed over the interval from 9 A.M. to 3 P.M. is 2.5 mph.

Explanation:

We can calculate the average speed as:

s = (s₁ + s₂) / n = (5 mph + 0 mph) / 2 = 2.5 mph

where:

s=average speed over the entire interval (9 A.M. to 3 P.M.)

s₁: average speed during the hiking (interval from 9A.M. to 12 A.M.)

s₂: average speed during the lunch (interval from 12 P.M to 3 P.M.)

n: number of intervals

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Neutrons released in a fission reaction can strike other nuclei and cause ______.
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Chain reactions

Neutrons released in a fission reaction can strike other nuclei and cause chain reactions

Explanation:

In nuclear fission reactions, the heavier atoms split into into lighter atoms, releasing neutrons at high velocity in the process. The neutrons hit other heavier atoms in the vicinity and split them too releasing more neutrons. This continuation is called chain reaction. The more the released neutrons the higher the rate of chain reactions. This causes too much energy to be produced at a go until an enormous explosion occurs (like in bombs).

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4 0
3 years ago
How do you do this? I know that the Density equation is D=m/v but these are in kilograms and Liters...so do I convert it to gram
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Explanation:

The problem doesn't specify that the units have to be g/mL, so you can calculate the density in kg/L without converting the mass or volume.

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4 years ago
When an object is moving with uniform circular motion, the centripetal acceleration of the object a. is circular. b. is perpendi
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A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 4.79 g coins stacked over the 28.8 cm mark, th
masha68 [24]

To solve the exercise, the key concept to be addressed is the Mass Center.

The center of mass of an object is measured as,

X_{cm} = \frac{\sum m_ix_i}{\sum m_i}

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

Our values are given by,

x_1 = 50cm

m_1 = ?

x_2 =28.8cm

m_2 = 4.79g

x_3 = 28.8cm

m_3 = 4.79g

X_{cm} = 38.4cm

Replacing the values in our previous equation we have,

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

38.4 = \frac{m_1(50)+2(28.8*4.79)}{m_1+2*4.79}

38.4(m_1+2*4.79)= m_1(50)+2(28.8*4.79)

38.4m_1 +367.872 = 50m_1+275.904

11.6m_1 = 91.968

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Therefore the mass of the meter stick is 7.928g

7 0
3 years ago
Can anyone Hele please I don't know how to convert the light years in order to get an equation like the one on Alpha Centauri in
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Answer:

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Explanation:

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