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aalyn [17]
3 years ago
7

Can anyone Hele please I don't know how to convert the light years in order to get an equation like the one on Alpha Centauri in

the picture, but I do know how to log it.

Physics
1 answer:
Svetradugi [14.3K]3 years ago
4 0

Answer:

Log 10 ( 4.16x10^16)

Explanation:

Other distance from sun you have to search by your self then apply the equation Log 10 ( distance from sun )

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Calculate the temperature increase in a 1.00-kg sample of water that results from the conversion of gravitational potential ener
Llana [10]

To solve this problem it is necessary to apply the concepts concerning the conservation of both potential and thermodynamic energy of the body. That is to say that as the body has a loss of potential energy it is gained in the form of thermal energy on water. If the potential energy is defined as

PE = mgh

Where,

m= mass

g = Gravitational acceleration

h = Height

And thermal energy is obtained as

Q = mC_p\Delta T

Where,

\Delta T = Change in Temperature

C_p = Specific Heat

m = Mass

We can equate this equation and rearrange to find the change at the Temperature, then

mgh = mC_p\Delta T

\Delta T = \frac{gh}{C_p}

Our values are given as,

C_p = 4186J/Kg\cdot K \rightarrow Specific Heat Water

Using energy conservation

g = 9.8m/s^2

h = 807m

Replacing,

\Delta T = \frac{(9.8)(807)}{4186}

\Delta T = 1.89K

Therefore the temperature increase in a 1kg sample of water is 1.89K

8 0
3 years ago
Make a list of all the possible human sources of carbon dioxide
ioda

Answer:

car fuel

production waste (like producing plastic, car, materials)

breathing

landfill

cement production

deforestation (cutting down trees)

burning of fossil fuels (coals, oil, natural gases)

Please mark Brainliest

Explanation:

7 0
3 years ago
A 5.0 kg wooden block is placed at an adjustable inclined plane. what is the angle of incline above which the block will start t
Aleks [24]
The value of the angle of the incline \theta at which the block starts to slide is the angle at which the component of the weight parallel to the incline becomes equal to the frictional force that keeps the block on the incline:
mg \sin \theta = \mu N
where the term on the left is the component of the weight parallel to the incline, and the term on the right is the frictional force, which is the product between the coefficient of friction \mu and the normal reaction of the incline N.

The normal reaction of the incline, N, is equal to the component of the weight perpendicular to the incline:
N=mg \cos \theta
Therefore, the initial equation becomes
mg \sin \theta = \mu mg \cos \theta
From which we find
\tan \theta = \mu
\theta = \arctan \mu

For angles above this value, the block will start sliding down, otherwise the block will stay on the incline.

3 0
3 years ago
Please help me with my question
Rufina [12.5K]
Number 1!!!!!!!!!!!!!

6 0
3 years ago
If a force of 26 N is exerted on two balls, one with a mass of 0.52 kg and the other with a mass of 0.78 kg, the ball with the m
gogolik [260]
False is the correct answer
6 0
3 years ago
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