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3 years ago

7

Can anyone Hele please I don't know how to convert the light years in order to get an equation like the one on Alpha Centauri in

the picture, but I do know how to log it.

1 answer:

Svetradugi [14.3K]3 years ago

4 0

Answer:

Log 10 ( 4.16x10^16)

Explanation:

Other distance from sun you have to search by your self then apply the equation Log 10 ( distance from sun )

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A steel ball is dropped from a building's roof and passes a window, taking 0.12 s to fall from the top to the bottom of the wind

Dvinal [7]

The top of the WINDOW is 19 meters from the ground. also steel balls dont bounce.

8 0

3 years ago

Use Coulomb’s law to derive the dimension for the permittivity of free space. <br><br><br><br>

MrRa [10]

Answer:

Coulomb's law is:

$F = \frac{1}{4*pi*e0} *(q1*q2)/r^2$

First, force has units of Newtons, the charges have units of Coulombs, and r, the distance, has units of meters, then, working only with the units we have:

N = (1/{e0})*C^2/m^2

then we have:

{e0} = C^2/(m^2*N)

And we know that N = kg*m/s^2

then the dimensions of e0 are:

{e0} = C^2*s^2/(m^3)

(current square per time square over cubed distance)

And knowing that a Faraday is:

F = C^2*S^2/m^2

The units of e0 are:

{e0} = F/m.

7 0

3 years ago

A source emits sound with a frequency of 860 Hz. It is moving at 20.0 m/s toward a stationary reflecting wall. If the speed of s

Galina-37 [17]

Answer:

$f_o=860\ Hz$

Explanation:

Given:

original frequency of sound wave, $f=860\ Hz$

speed of the sound source, $v_s=20\ m.s^{-1}$

original speed of sound wave from the source, $s=343\ m.s^{-1}$

<u>According to the Doppler's effect:</u>

$\frac{f_s}{f_o} =\frac{s+v_s}{s-v_o}$

The sound is reflected from the wall and the source is moving towards the wall and observer is also riding the same source.

The velocity of the observer, $v_o=-20\ m.s^{-1}$

$\frac{860}{f_o} =\frac{s+20}{s-(-20)}$

$f_o=860\ Hz$

3 0

3 years ago

Read 2 more answers

1. Most of the stars on the HR Diagram are classified as which type of star?

xenn [34]

Answer:

1. Main Sequence - middle life 17

2. red

3. blue

4. White dwarf stars are much hotter than Red Supergiants 15. List the color of the stars from hottest to coldest: Blue, White, Yellow, Orange, Red 16.

5. red giants

Explanation:

Main sequence stars have a Morgan-Keenan luminosity class labeled V. red giant and supergiant stars (luminosity classes I through III) occupy the region above the main sequence. They have low surface temperatures and high luminosities which, according to the Stefan-Boltzmann law, means they also have large radii. White dwarf stars are much hotter than Red Supergiants 15. List the color of the stars from hottest to coldest: Blue, White, Yellow, Orange, Red 16. The hottest stars are the blue stars. A star appears blue once its surface temperature gets above 10,000 Kelvin, or so, a star will appear blue to our eyes. The lowest temperature stars are red while the hottest stars are blue. Astronomers are able to measure the temperatures of the surfaces of stars by comparing their spectra to the spectrum of a black body. Most stars, including the sun, are "main sequence stars," fueled by nuclear fusion converting hydrogen into helium. ...

As stars begin to die, they become giants and supergiants (above the main sequence).

5 0

3 years ago

Read 2 more answers

A possible means for making an airplane invisible to radar is to coat the plane with an antireflective polymer. If radar waves h

Marina CMI [18]

Answer:

The thickness is $t = 0.5615 \ cm$

Explanation:

From the question we are told that

The wavelength of the of the rader waves is $\lambda = 2.92 \ cm$

The index of refraction of the polymer is $n = 1.30$

The thickness is mathematically represented as

$t = \frac{\lambda }{4 n }$

Substituting values

$t = \frac{2.92}{4 * 1.30 }$

$t = 0.5615 \ cm$

6 0

3 years ago