Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
The percent error is 34.28 %.
Hope this helps! Be safe out there.
Answer:
area = 6x^2+10x-4 perimeter= 5x+3
Step-by-step explanation:
Answer:
The first one is 0 slope.
The second one undefined slope.
Step-by-step explanation:
I hope it helps you!!!:-)
