3 years ago

How do I solve this problem

Mathematics

2 answers:

ExtremeBDS [4]3 years ago

8 0

$9p > 63\ \ \ \ |:9\\\\p > 7\\--------------\\\\\dfrac{p}{3}\leq2\ \ \ \ |\cdot3\\\\p\leq6$

Answer:

On the picture.

$p\in(-\infty;\ 6]\ \cup\ (7,\ \infty)$

Vanyuwa [196]3 years ago

6 0

$\bf 9p>63\implies p>\cfrac{63}{9}\implies \boxed{p>7}\\\\\\\cfrac{p}{3}\le 2\implies \boxed{p\le 6}$

check the picture below.

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