Help me solve this logical question.

1. The scale on a map reads 3 inches = 25 miles.

KonstantinChe [14]

Answer:

D. 62.5

Step-by-step explanation:

2 ways

1.

7.5 ÷ 3 = 2.5

25 times 2.5 = 62.5

2.

3/7.5 = 25/x

3x = 187.5

187.5 ÷ 3 = 62.5

3 0

1 year ago

Gage is building a model rocket for a science fair project. He attaches a nosecone to a cylindrical body to form the rocket's fu

denpristay [2]

Answer:

305.78 in2

Step-by-step explanation:

The rocket has two parts: one is a cylinder and the other is a cone.

To find the total volume of the rocket, we need to find firstly the volume of each part.

The cylinder has a radius of 2 inches and a height of 2*12 + 5 - 7 = 22 inches, so its volume is:

V1 = pi * r^2 * h = pi * 2^2 * 22 = 276.46 in2

The cone has a radius of 2 inches and a height of 7 inches, so its volume is:

V2 = (1/3) * pi * r^2 * h = (1/3) * pi * 2^2 * 7 = 29.32 in2

Then, we have that the volume of the rocket is:

V = V1 + V2 = 276.46 + 29.32 = 305.78 in2

3 0

2 years ago

What is x(10+6x) simplified

Irina18 [472]

See attachment for the 3 Answers.

8 0

2 years ago

Read 2 more answers

PLEASE HELP GUYS i am struggling so much, two questions

ankoles [38]

Answer: the equation of the standard parabola

1) $(y-6)^2 = 4 (x-1)$

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

Explanation

Parabola:-

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

The locus of P such that $\frac{SP}{PM} = constant$
The fixed point 'S' is called the Focus.
The fixed line'l 'is called the directrix of the conic
The constant ratio is known as the eccentricity, denoted by 'e'
If e=1 , the conic is called a parabola

1) Step 1 :-

Given the focus S = (2,6) and directrix is x=0

we know that $\frac{SP}{PM}=1$

now cross multiplication , we get

$SP = PM$

squaring on both sides,we get

$SP^{2} = PM^2$

step 2:-

now using distance formula is

$\sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)$

Given S =(2,6) and P(x,y) be any point on parabola

$SP^2 = (x-2)^2+(y-6)^2$ ........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

$\frac{ax_{1}+by_{1}+c }{\sqrt{a^2+b^2} }$

Given the directrix is x =0 and P(x,y) be any point on parabola

$PM^2 = \frac{x^2}{\sqrt{1}^2 }$ ......(2)

equating equation(1) and equation (2), on simplification

we get $(x-2)^2+(y-6)^2 = x^2$ .....(3)

apply $(a-b)^2 = a^2+ b^2+2 ab$

now the equation (3) is

$(y-6)^2 = 4 x-4$

now the standard form of parabola is

$(y-k)^2 = 4 a(x-h)$

Final answer:-

$(y-6)^2 = 4 (x-1)$

2) Explanation:-

step 1:

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

$(x-h)^2 = 4 a (y-k)$

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of $AS = \sqrt{(-5-(-5)^2+(2-6)^2}$

on simplification we get a =4

Final answer :-

the vertex (h,k) = (-5,2) and a=4

$(x-h)^2 = 4 a (y-k)$

The standard parabola is $(x+5)^2 = 16 (y-2)$

5 0

2 years ago

Write a recursive formula for the sequence -1,-2,-3,-4...

myrzilka [38]

Answer:

f(1) = -1

f(n) = f(n-1) -1

Step-by-step explanation:

The first term is -1. Each term is 1 less than the previous. These equations say that.

f(1) = -1

f(n) = f(n-1) -1

7 0

3 years ago

Help me solve this logical question. ​

Help me solve this logical question.