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3 years ago

I need quick help pls!!!!!!

Mathematics

2 answers:

goldenfox [79]3 years ago

7 0

Answer: i don,t know sorry but i wish you the best of luck

Step-by-step explanation:

Semmy [17]3 years ago

6 0

Answer:

do the math

Step-by-step explanation:

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Create a circle such that its center is point a and b is a point on the circle

Angelina_Jolie [31]

Step-by-step explanation:

The center of a circle is the point in the circle which is equidistant to all the edges of thr circle. The point a is the center, while point b is an arbitrary point in the circle. Find attachment for the diagram.

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3 years ago

1-2n) - 7n(12-2) simplify this and show work

Natasha2012 [34]

For this case we must simplify the following expression:

$(1-2n) -7n (12-2) =$

We solve the operation of the second parenthesis, taking into account that different signs are subtracted and the sign of the major is placed:

$(1-2n) -7n (10) =$

We multiply:

$(1-2n) -70n =$

We eliminate the parentheses:

$1-2n-70n =$

We add similar terms, taking into account that equal signs are added and the same sign is placed:

$1-72n$

Answer:

The simplified expression is: $1-72n$

5 0

3 years ago

A line segment or ray that is perpendicular to the segment at its midpoint is called

Dimas [21]

Perpendicular bisector

3 0

3 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .