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Likurg_2 [28]
3 years ago
9

amari is standing 50 feet from the base of a building. from where he stands, the angle formed from the top of the building to wh

ere he stands is 60 degrees. how tall is the building?

Mathematics
2 answers:
allsm [11]3 years ago
7 0
Approximately 86.8 ft. 
lisabon 2012 [21]3 years ago
5 0
Drawing it out from the top of the building as shown (we get 30 degrees because if the bottom angle is 60 and there's a right angle, 180-60-90=30),  tan30=opposite/adjacent = 1/sqrt(3)=50/x Multiplying each side by x and dividing by 1/sqrt(3), we get that 
x=50/(1/sqrt(3))= around 86.6 ft

If it's 60 degrees instead of 30,
tan60=opposite/adjacent = sqrt(3)=50/x Multiplying each side by x and dividing by sqrt(3), we get that 
x=50/sqrt(3)= around 28.87

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Step-by-step explanation:

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3 years ago
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Vesnalui [34]

Answer:

Option B. x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

Step-by-step explanation:

we know that

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x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

14x^{2}+9x+10=0

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Remember that

i=\sqrt{-1}

substitute

x=\frac{-9(+/-)\sqrt{479}i} {28}  

x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

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Step-by-step explanation:

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Step-by-step explanation:

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