Answer:
D. (1/4, -2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -8x
4x - y = 3
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 4x - (-8x) = 3
- Simplify: 4x + 8x = 3
- Combine like terms: 12x = 3
- Isolate <em>x</em>: x = 3/12
- Simplify: x = 1/4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: y = -8x
- Substitute in <em>x</em>: y = -8(1/4)
- Multiply: y = -2
Answer: B
Step-by-step explanation:
Answer:
s > 200
Step-by-step explanation:
Note that
> means greater than
< means less than
for example : 2 < 3 means 2 is less than 3
3 >2 means 3 is greater than 2
If he needs to sell more than 200, sales has to be greater than 200 = s > 200
Answer:
B
Step-by-step explanation:
The point starts at 250 on the Y-Axis
Eq. 1 .10x + .25y = 9.45
Eq. 2 x + y = 60 rewrite as x = 60 - y and substitute into equation 1.
.10(60 - y) + .25y = 9.45
6 - .1y + .25y = 9.45
6 + .15y = 9.45
.15y = 3.45
y = 23
60 - 23 = 37
23 quarters
37 dimes
23* .25 = 5.75
37 * .1 = 3.70
5.75 + 3.70 =9.45
