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il63 [147K]
3 years ago
14

Determine the critical value or values for a one-mean z-test at the 10% significance level if the hypothesis test is left-tailed

(Ha:μ<μ0).z0.10 1.282z0.05 1.645z0.025 1.960z0.01 2.326z0.005 2.576
Mathematics
1 answer:
Ugo [173]3 years ago
5 0

Answer: 1.282

Step-by-step explanation:

Given : Significance level : \alpha= 10\%=0.10

The alternative hypothesis : H_a:\mu, which is left tail-ed , it means the test is left -tailed test i.e. one -tailed test.

By using the standard normal distribution table , we have

The critical value for a one-mean z-test corresponding to the significance level 0.10 is 1.2815515 or approximately 1.282

Hence, the  critical value or values for a one-mean z-test at the 10% significance level if the hypothesis test is left-tailed = 1.282

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The line with equation a + 4b = 0 coincides with the terminal side of an angle θ in standard position and cos θ &gt; 0. What is
ankoles [38]

Answer:

Option A. -(\frac{\sqrt{17}}{17})

Step-by-step explanation:

Equation of a given line is a + 4b = 0 or b = -\frac{1}{4}a

This in the form of y = mx + b, which is slope-intercept form.

Here slope of the line is (-\frac{1}{4}).

Or tanθ = \frac{(-1)}{4}

This line coincides with the terminal side of the angle in standard position where cosθ > 0

Since tanθ = \frac{\text{Height}}{\text{Base}}

and sinθ = \frac{\text{height}}{\txt{Hypotenuse}}

Hypotenuse = \sqrt{\text{height}^{2}+\text{Base}^{2}}

                     = \sqrt{(1^{2}+4^{2})}

                     = \sqrt{17}

Since tanθ is negative and cosθ > 0 that means θ lie in fourth quadrant.

Therefore, sinθ will be negative.

[ \frac{-sin\theta}{+cos\theta}=-tan\theta ]

sinθ = -\frac{1}{\sqrt{17}}

       = -\frac{1}{\sqrt{17}}\times \frac{\sqrt{17} }{\sqrt{17}} = -\frac{\sqrt{17}}{17}

Answer will be option A.

6 0
4 years ago
For a moving object, the force acting on the object varles directly with the object's acceleration. When a force of 25 N acts on
Radda [10]

\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}

According to the Question,

\large{\sf{ f \propto \: a}}

<h3>From the Question,</h3>

  • Initial Acceleration,a = 5 m/s²

  • Force at a = 5 m/s²,f = 25 N

  • Final Acceleration,A = 9 m/s²

<h3>To find</h3>

Force exerted on the object at a = 9 m/s²

We Know that,

\huge{\boxed{ \boxed{ \sf{f = ma}}}}

Firstly,we need to find the mass of the object

Thus,

\sf{m =  \frac{f}{a} } \\  \\  \implies \:  \sf{m =  \frac{25}{5} } \\  \\  \huge{ \implies \:  \sf{m = 5 \: kg}}

Now,

\sf{F = mA} \\  \\  \implies \:  \sf{F = (5)(9)} \\  \\  \huge{ \implies \:  \sf{F = 45 \: N}}

7 0
3 years ago
Can y’all help me please
likoan [24]

Answer:

y = -4x + 60

Step-by-step explanation:

(0, 60) and (4,44)

Slope:

m=(y2-y1)/(x2-x1)

m=(44 - 60)/(4-0)

m= (-16)/4

m= -4

Slope-intercept:

y - y1 = m(x - x1)

y - 60 = -4(x - 0)

y - 60 = -4x

y = -4x + 60

8 0
3 years ago
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A map has a scale of 2 inches : 25 miles. Chandra uses the map to find the distance from the zoo to her house. The distance on t
geniusboy [140]

Step-by-step explanation:

Turn the ratio into a fraction

2in /25 mi

You want to have miles so you can flip the fraction and mutiply to cancel out the inches

(25mi / 2in) x 5in = (25 mi x 5in) / 2in

5 0
3 years ago
Does someone have this answer???? Thank you so much
fredd [130]

Answer: 3

Step-by-step explanation:

We know that p(t) = 11:

11=2t+5

11-5=2t

6=2t

6/2 = t

3 = t

5 0
3 years ago
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