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morpeh [17]
2 years ago
6

A map has a scale of 2 inches : 25 miles. Chandra uses the map to find the distance from the zoo to her house. The distance on t

he map is 5 inches. How many miles away is the zoo from Chandra’s house?
Mathematics
1 answer:
geniusboy [140]2 years ago
5 0

Step-by-step explanation:

Turn the ratio into a fraction

2in /25 mi

You want to have miles so you can flip the fraction and mutiply to cancel out the inches

(25mi / 2in) x 5in = (25 mi x 5in) / 2in

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-5

Step-by-step explanation:

There is different ways to solve methods of elimination but if you wanted to cancel y out you would multiply by the opposite sign....for example

7x + 5y = 19

-5 (2x + y = 19) ---> -10x -5y = 95

this would cancel out your y to solve for x so you can plug it back in and solve! hope this helps!!!

6 0
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Match the correct angle measurement with its letter from the diagram.
igor_vitrenko [27]

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What is 12 out of 18 in lowest terms?
masya89 [10]
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5 0
3 years ago
Show me how you solve it
julia-pushkina [17]

Answer:

5^20

Step-by-step explanation:

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u>

\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n} }

Therefore:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  }

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u><u>I</u>

\displaystyle \large{( {a}^{m} ) ^{n} =  {a}^{m \times n}  }

Thus:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  = {5}^{5 \times 4}   } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =   {5}^{20} }

7 0
3 years ago
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