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3 years ago

I need to find the area .

Mathematics

1 answer:

nikklg [1K]3 years ago

5 0

Answer:

104 ft^2

Step-by-step explanation:

area of rectangle = 8 × 10 = 80

area of triangle = 1/2 × 6 × 8 = 24

∴total area = 104 ft^2

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Taylor is comparing the prices of two mattress cleaning companies. Company A charges $30 per mattress and an additional $15 as s

Oduvanchick [21]

part A:

company a

30m+15

m= matress

company b

28m+21

m=matresses sold

part B:

company a

30(6)+15

195$

company b

28(6)+21

189$

company B charges less

part C:

company a

30(3)+15

105$

company b

28(3)+21

105$

there is no change at all so you do not save anything.

3 0

3 years ago

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0

3 years ago

Read 2 more answers

- 11/5 -2.4 1.6 15/10 - 2.25 in order from least to greatest

tatuchka [14]

Answer (least to greatest):

-2.4
-2.25
-11/5
15/10
1.6

I hope this helps!

8 0

3 years ago

Read 2 more answers

Section 5.2 Problem 6: Find the general solution <img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2

mihalych1998 [28]

Answer:

$y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Step-by-step explanation:

Given Second-Order Homogenous Differential Equation

$y''+6y'+10y=0$

Use Auxiliary Equation

$m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i$

General Solution

$y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Note that the DE has two distinct complex solutions $p\pm qi$ where $A$ and $B$ are arbitrary constants.

4 0

2 years ago

Please helpppppppppppppppppppppppppppppppppppp

Pani-rosa [81]

Step-by-step explanation:

(2×10^8)(2×10^-2)
4×10^8+(-2)
4×10^6

<h3>stay safe healthy and happy.</h3>

6 0

3 years ago

Read 2 more answers