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3 years ago

6

Ill give brainliest to someone who answers first

1 answer:

Mars2501 [29]3 years ago

6 0

It is 28 pounds. This is because all of the others have a ratio of 4:1 while 28 and 5.5 have a ratio of 56:13.

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There are 527 pencils,646 erasers,748 sharpeners . these are to be put in separate packets containing the same no. of items. fin

Ksju [112]

$To \; find \; the \; maximum \; number \; of \; items \; possible \; in each \; packet,\\we \; need \; to \; find \; the \; Greatest \; Common \; Factor\\ \; of \; 527 \; Pencils, \; 646 \; erasers \; and \; 748 \; sharpeners.\\\\We \; need \; to \; list \; the \; Factors \; of \; each \; number \; as \; given \; below\\ \; and \; identify \; the \; greatest \; common \; factor.$

$The \; factors \; of \; 527 \; are:\\1, \; 17, \; 31, \; 527\\\\The \; factors \; of \; 646 \; are:\\1, \; 2, \; 17, \; 19, \; 34, \; 38, \; 323, \; 646\\\\The \; factors \; of \; 748 \; are:\\1, \; 2, \; 4, \; 11, \; 17, \; 22, \; 34, \; 44, \; 68, \; 187, \; 374, \; 748\\\\Then \; the \; greatest \; common \; factor \; is \; 17.$

$Conclusion: \\There \; will \; 31 \; Pencils, \; 38 \; Erasers,\\ \; and \; 44 \; Sharpeners \; in \; each \; of \; SEVENTEEN \; packet.$

4 0

3 years ago

Jorge baked cookies for his math class's end-of-year party. There are 28 people in Jorge's math class including Jorge and his te

timurjin [86]

You have to multiply the number of people times the number of cookies they are each supposed to get

So, 28 x 3 = 84 cookies

7 0

3 years ago

AHHHHHHHHHHHHHHH SOMEONE ANSWEER THIS PLEEASEEE NEED ANSWER ASP 20 pts!! Please answer!!! I literally don't get this ;c so PLEAS

Blababa [14]

Answer:

$P(A\textrm{ and }B)=\frac{3}{14}$

Step-by-step explanation:

Given:

$P(A)=\frac{4}{7}$

$P(B|A)=\frac{3}{8}$

We know that, conditional probability of B given that A has occurred is given as:

$P(B|A)=\frac{P(A\cap B}{P(A)}$ . Expressing this in terms of $P(A\cap B)$ , we get

$P(A\cap B)=P(B|A)\times P(A)$

Plug in the known values and solve for $P(A\cap B)$ . This gives,

$P(A\cap B)=P(B|A)\times P(A)\\P(A\cap B)=\frac{3}{8}\times \frac{4}{7}\\P(A\cap B)=\frac{12}{56}=\frac{3}{14}$

Therefore, the probability of events A and B occurring is $\frac{3}{14}$ .

6 0

3 years ago

Read 2 more answers

The value of 2 to the 3rd power + 3 to the 3 power = ___.

Arturiano [62]

35.

2*2= 4*2=8

3*3=9*3=27

27+8=35

So the answer is 35. Hope this helps

3 0

3 years ago

Read 2 more answers

Altlantic Auditorium has 1500 seats. Tickets were sold for 900 of the seats. for what percent of the seats were tickets sold?

muminat

60%, 900/1500 would be .6 and in terms of percent would be 60.

3 0

3 years ago