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solniwko [45]
4 years ago
10

If vector u = <-3.5, -1.5> and vector v = <-1.25, 2.25>, which graph shows the resulting vector for 2v − u?

Mathematics
1 answer:
lana [24]4 years ago
5 0

Answer:

See the attached figure.

Given:

u = (-3.5 , -1.5) and v = (-1.25 , 2.25)

So,

2v = 2 * (-1.25 , 2.25) = (-2.5, 4.5)

∴ 2v - u = (-2.5, 4.5) - (-3.5 , -1.5) = (1 , 6)

The graph of the vectors is as shown in the attached figure.

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3 years ago
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Choose a linear function for the line represented by the point-slope equation y - 5 = 3(x - 2).
FromTheMoon [43]

f(x) = 3x - 1

Step-by-step explanation:

y - 5 = 3(x - 2) \\ y - 5 = 3x - 6 \\ y = 3x - 6 + 5 \\ y = 3x - 1

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3 years ago
Divide and write in simplest form.
iren2701 [21]

Answer:

1. \frac{3}{17} (3/17)

2. \frac{3}{7} (3/7)

3.  \frac{45}{184} (45/184)

Step-by-step explanation:

1. \frac{\frac{3}{5} }{3\frac{2}{5}} = \frac{\frac{3}{5} }{\frac{17}{5}} = \frac{\frac{3}{1} }{\frac{17}{1}}= \frac{3}{17}

2. \frac{2}{4\frac{2}{3}} = \frac{\frac{2}{1} }{\frac{14}{3}}= \frac{2}{1} /\frac{14}{3} = \frac{2}{1} *\frac{3}{14} = \frac{6}{14} = \frac{3}{7}

3. \frac{\frac{5}{4} }{5\frac{1}{9} } = \frac{\frac{5}{4} }{\frac{46}{9}} = \frac{5}{4}/\frac{46}{9} = \frac{5}{2}/\frac{23}{9} = \frac{5}{2}*\frac{9}{23} = \frac{45}{184}

Hope this helps!

4 0
3 years ago
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xxTIMURxx [149]

Answer: (3,45) and (15,9)

Step-by-step explanation:

LCM x HCF = 45*3 = 135

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Mice21 [21]

Answer:

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Step-by-step explanation:

The computation of the width of the photograph is as follows:

As we know that

Area of the rectangle = length × width

33 ÷ 20 square inches = 1475 inches × width

So, the width is

= Length ÷ area

=  1475 inches ÷ (33 ÷ 20 square inches)

= 1.12 × 10^-3

8 0
3 years ago
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