Angles B And W are supplementary. Angle B has a measure of (4x+16) .Angle W has a measure of 68 .what is the value of x

A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true

zloy xaker [14]

Answer:

The probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

As the sample size is large, i.e. n = 492 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by the normal distribution.

The mean and standard deviation of the sampling distribution of sample proportion are:

$\mu_{\hat p}=p=0.07\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.07(1-0.07)}{492}}=0.012$

Compute the probability that the sample proportion will differ from the population proportion by greater than 0.03 as follows:

$P(|\hat p-p|>0.03)=P(|\frac{\hat p-p}{\sigma_{\hat p}}|>\frac{0.03}{0.012})$

$=P(|Z|>2.61)\\\\=1-P(|Z|\leq 2.61)\\\\=1-P(-2.61\leq Z\leq 2.61)\\\\=1-[P(Z\leq 2.61)-P(Z\leq -2.61)]\\\\=1-0.9955+0.0045\\\\=0.0090$

Thus, the probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

5 0

3 years ago

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Debora [2.8K]

Answer:

6

Step-by-step explanation:

This problem centers on recognizing the relationship between fractions and repeating decimals.

Note the following:

$\frac{1}{3}=0.33333333333333333333333333333333333333333333333...$

or more simply $\frac{1}{3}=0.\bar{3}$

This means that $2\frac{1}{3}=2.\bar{3}$

Going back to the original expression, $3\frac{2}{3}+2.\bar{3}$ simplifies to $3\frac{2}{3}+2\frac{1}{3}$

Next, adding mixed numbers. For adding mixed numbers, whole number parts and fractional parts can be added separately (this is because of the associative and commutative properties of addition)... because

$3\frac{2}{3}+2\frac{1}{3}$ means the same thing as

$(3+\frac{2}{3})+(2+\frac{1}{3})$

Changing the order, we can write it as

$3+2+\frac{2}{3}+\frac{1}{3}$

Adding the whole number parts, 3+2 is 5.

Next, adding the fraction parts:

For adding fractions, one must have a common denominator (the bottom part of the fraction must be the same). Once they are the same, the denominator just sort of "hangs out" until the end without changing, and the numerators (the tops) are added together.

Fortunately, the denominators are already the same. So, add the numerators, and the denominator will stay as a 3.

$\frac{2}{3}+\frac{1}{3}$