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Luba_88 [7]
4 years ago
13

Simplify 2(x+3)-4 showing each step

Mathematics
2 answers:
Alex4 years ago
7 0
To simplify this, we first need to distribute the 2 into the parenthesis.

= 2 * x + 2 * 3 - 4

Now, we can simplify:

= 2x + 6 - 4
= 2x + 2

Hope this helps!
krek1111 [17]4 years ago
6 0
Okay, we want to start with having the original expression for the first step.

2(x+3)-4
We can use distributive property to get rid of the parenthesis. So I will be multiplying everything inside the parenthesis by the 2.

2x + 6 - 4
The reason I didn’t multiply the four by two was because the four is outside of the parenthesis. Right now, we can add like terms. Four is basically negative since it has a subtraction sign outside of it and six is positive ( this is the same as doing 6-4, I’m just calling it negative because as you get used to simplifying expressions, you have to think of it that way).

6+(-4)=6-4=2
Now we have all the like terms added, we can find our simplified expression.
2x+2
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0.7619047619 as a fraction? <br> which one<br> 1. 1/16 <br> 2. 16/21 <br> 3. 2 <br> 4. 4
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3 years ago
| 7 + m | - 4 &gt; 8
cestrela7 [59]

Answer:

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Step-by-step explanation:

We are given the Inequality:

\displaystyle \large{ |7 + m|  - 4 > 8}

First, add both sides by 4.

\displaystyle \large{ |7 + m|  - 4 + 4 > 8 + 4} \\  \displaystyle \large{ |7 + m|  > 12}

<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u>

\displaystyle \large{ |a|  =  \sqrt{ {a}^{2} } }

Given a = any expressions and b = any positive numbers, zero or any expressions.

\displaystyle \large{ |a|  =  b \longrightarrow a =  \pm b}

From the Inequality, change > to equal

\displaystyle \large{ 7 + m   =   \pm12}

Subtract 7 both sides.

\displaystyle \large{  7 - 7 + m   =  \pm12 - 7} \\ \displaystyle \large{  m   =   \pm12 - 7}

±12-7 can be 12-7 = 5 or -12-7 = -19

\displaystyle \large{  m   =   5, - 19}

Refer to the attachment. The region is when the absolute value function is greater than constant function y = 12 or a blue horizontal line.

Since the absolute graph is above constant graph when x > 5 and x <-19.

Therefore,

\displaystyle \large{  m    >  5, m < - 19}

3 0
3 years ago
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