<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer:
1/250 W/m² or 0.004 W/m² or 4 mW/m²
Step-by-step explanation:
The cargo worker is (50 m)/(1 m) = 50 times the reference distance. The intensity varies as the inverse of the square of the distance, so will be ...
(1/50)²×(10 W/m²) = 10/2500 W/m² = 1/250 W/m²
This might be more conveniently written as 4 mW/m².
I will be there at the same time I don't hear
Lets try 96
4 x ?= 96
? = 96/4
= 24
So we see that 4 times 24 is close to 97.
You would use 1.73 in order to decrease an amount by 73%
