Question

Solve open parentheses square root of 7 close parentheses to the 6 x power = 49x−6.

Answer 1

Answer:

Option D is correct.

x = -12

Step-by-step explanation:

Solve:  $(\sqrt{7})^{6x} = 49^{x-6}$

We can write 49 as:

$49 = 7 \cdot 7 = 7^2$

using exponent rules:

$\sqrt[n]{a^m}=a^{\frac{m}{n}}$

$(a^m)^n = a^{mn}$

Apply this rules on the given equation:

$((7)^{\frac{1}{2}})^{6x} = (7^2)^{x-6}$

$7^{\frac{6x}{2}} = 7^{2(x-6)}$

Simplify:

$7^{3x} =7^{2x-12}$

On comparing both sides we get;

$3x = 2x-12$

Subtract 2x from both sides we get;

x = -12

Therefore, the value of x is -12

Answer 2

The equation is not setup properly, possibly it is your teacher's fault.

From external research, I would say the answer is x = -12.