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3 years ago

Evaluate 2x + y, for x = 1/3 and Y=2/3A. 1/3B. 2/3C. 4/3D. 5/3

Mathematics

2 answers:

larisa86 [58]3 years ago

6 0

The answer is C)4/3
Hope this helps!!!

Alex_Xolod [135]3 years ago

4 0

The answer would be C. 4/3 because 2 time 1/3 would be 2/3 and then you would add y which is 2/3 and you'll get C

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6.1 Write Linear Equations in Slope-Intercept Form

Aliun [14]

Answer:

The answer to the question provided is

1. y = 4x - 3.

2. y = -2x - 2.

6 0

3 years ago

What is the simplified version of <img src="https://tex.z-dn.net/?f=%282%5Csqrt%7B5%7D%2B3%29%28%5Csqrt%7B5%7D-1%29" id="TexForm

Tpy6a [65]

ANSWER

EXPLANATION

We want to simplify:

$(2\sqrt{5}+3)(\sqrt{5}-1)$

Recall the distributive property;

(a+b)(c+d)=a(c+d)+b(c+d)

We apply this property to get,

$2\sqrt{5}(\sqrt{5}-1) + 3(\sqrt{5}-1)$

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$10 + \sqrt{5}-3$

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$7 + \sqrt{5}$

7 0

4 years ago

Graph 24x+25=−6y+7 .

MrRa [10]

Okay, So you have 24x+25=6y+7

Step 1: Pull out like factors : 24x + 18 + 6y = 6 • (4x + y + 3)

Step 2: 4x+y+3 = 0

y-intercept = -3/1 = -3.00000

x-intercept = -3/4 = -0.75000

Slope = -8.000/2.000 = -4.000

And bam, you have a straight line

5 0

4 years ago

Joan multiplied 9.1 by 10 1.

nataly862011 [7]

It will be greater than 9.1 if he multiplied by 10.1

7 0

3 years ago

A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an

liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

when the angle is 30 degrees

$tan(30) = \frac{6000}{d1}$

$d1 = \frac{6000}{tan(30)}$

$d1 = \frac{6000}{0.577}$

d1 = 10392.3 meters

when the angle is 60 degrees

$tan(60) = \frac{6000}{d2}$

$d2 = \frac{6000}{tan(60)}$

$d2 = \frac{6000}{1.732}\\$

d2 = 3464.1 meters

distance travelled by aircraft in 1 min is

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

Now converting to m/sec

=> $\frac{6928.2}{60}$

=>115.47 m/sec

4 0

3 years ago