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3 years ago

Tourists from a tour bus were asked about places they visited during their stay in a city. The results are shown in the table.

1 answer:

7 0

<span>Given:

visited museum   didn't visit museum Total

visited zoo 9   14 23

didn't visit zoo   5 2 7

Total 14 16 30

Simply look at the table and check the number that corresponds to visitors who visited the museum but did not visit the zoo. The number is 5.
Divide it by the total number of people surveyed. Total is 30.

Probability visited the museum but did not visit the zoo = 5/30 = 0.16666 or 16.67%</span>

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A salsa recipe uses green pepper, onion, and tomato in the extended ratio 2:5:9. How many cups of onion are needed to make 96 cu

son4ous [18]

2x+5x+9x=96
16x=96
X=6

Green peppers =2*6=12
Onions=5*6=30
Tomato =9*6=64

Onions are 30

3 0

3 years ago

Ben drinks tea at an incredible rate.He drinks 3 1/2 liters of tea every 2/3 of an hour.Ben drinks tea a constant rate.How many

vampirchik [111]

Answer:

Step-by-step explanation:

2/3 = 0.66

1 hour = 60

60 x 0.66 = 39.6 or 40

In which, 60 - 40 = 20; so he only drinks 3 1/2 liters every 40 minutes.

He drinks 3 1/2 every hour.

3 0

3 years ago

Evelyn drinks A glass of water a day which is 56 glasses of water in a week how many glasses of water dish does she drink in a y

Ede4ka [16]

Answer:

2912

Step-by-step explanation:

Your question wording is a little confusing but here's the steps:

She drinks 56 glasses of water each week.

There's 52 weeks in 1 year.

56 times 52 = 2912.

3 0

2 years ago

7 × [(25 − 2) − (2 + 3)]

oee [108]

Answer:

126

Step-by-step explanation:

25-2=23

2+3=5

23-5=18

7*18=126

8 0

3 years ago

A survey of 225 students showed the mean number of hours spent studying per week was 20.6 and the standard deviations was 2.7

LekaFEV [45]

Answer:

The margin of error is approximately 0.3

Step-by-step explanation:

The following information has been provided;

The sample size, n =225 students

The sample mean number of hours spent studying per week = 20.6

The standard deviation = 2.7

The question requires us to determine the margin of error that would be associated with a 90% confidence level. In constructing confidence intervals of the population mean, the margin of error is defined as;

The product of the associated z-score and the standard error of the sample mean. The standard error of the sample mean is calculated as;

$\frac{sigma}{\sqrt{n} }$

where sigma is the standard deviation and n the sample size. The z-score associated with a 90% confidence level, from the given table, is 1.645.

The margin of error is thus;

$1.645*\frac{2.7}{\sqrt{225}}=0.2961$

Therefore, the margin of error is approximately 0.3

5 0

3 years ago

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