The perimeter of the triangle is 40 units
<h3>Perimeter of a triangle</h3>
From the question, we are to determine the perimeter of the given triangle
From the given diagram, we can observe that the triangle is a right triangle
The vertical length of the triangle is 15 units
and the horizontal length of the triangle is 8 units
Thus,
We can find the hypotenuse by using the<em> Pythagorean theorem </em>
Let the hypotenuse be h
Then,
h² = 15² + 8²
h² = 225 + 64
h² = 289
h = √289
h = 17 units
Now, for the perimeter of the triangle
The perimeter of a triangle is the sum of all its three sides
Thus,
The perimeter. P, of the triangle is
P = 15 + 8 + 17
P = 40 units
Hence, the perimeter of the triangle is 40 units
Learn more on Calculating perimeter here: brainly.com/question/17394545
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(-4,0) and (0,8)
(8-0)/(0+4)= 8/4= 2
y - 0 = 2(x + 4)
y = 2x + 8
Answer:
3.15 and 3 3/20
Step-by-step explanation:
315 ÷ 100 = 3.15
3.15 = 3 3/20
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Answer:
∠ C = 36°
∠ D= 81°
∠ DEC= 63°
Step-by-step explanation:
<em>The exterior angle of a triangle is equal to the sum of the interior opposite angles. </em>
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∴ (11y + 4) + (5y + 1) = 117
11y + 4 + 5y + 1 = 117
16y + 5 = 117
16y = 117-5
16y = 112
y = 112÷16
y = 7
∠ C = 5×(7) + 1 = 36°
∠ D = 11×(7) + 4 = 81°
∠ DEC = 180- 117 = 63°
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Answer: -102
Step-by-step explanation: First we do 9-3 = 6, then add -6 which cancels each other out, so all we have left is -102.
Hope this helps! :)
