54 quarter hours ... 36 semester hours
87 quarter hours ... x semester hours = ?
If you would like to know how many semester hours credit would a student receive after completing 87 quarter hours, you can calculate this using the following steps:
54 * x = 87 * 36
54 * x = 3132 /54
x = 3132 / 54
x = 58
Result: A student with 87 quarter hours is given credit for 58 semester hours.
Answer:
D) very likely
Step-by-step explanation:
The possible outcomes are 1,2,3,4,5,6
Between means 2,3,4,5
A) certain it is not certain because we could get 1 or 6
B) unlikely we have a 4/6 change of getting our number rolled so it is not unlikely
C) impossible we have a 4/6 change of getting our number rolled so it is not impossible
D) very likely we have a 4/6 change of getting our number rolled so it is better than 50 % we will have one of our numbers rolled
Answer:
(-1,-4)
Step-by-step explanation:
Using the rule of when we rotate 90 degrees clockwise
(x,y) goes to (y,-x). We plug it in.
(4,-1) goes to (-1,-4).
Answer:
-no solution-
Step-by-step explanation:
Let's solve your system by elimination.
−6x+2y=−14;−9x+3y=−21
Multiply the first equation by 3,and multiply the second equation by -2.
3(−6x+2y=−14)
−2(−9x+3y=−21)
Becomes:
−18x+6y=−42
18x−6y=42
Add these equations to eliminate y:
0=0
Answer:
Infinitely many solutions.
Let's solve your system by substitution.
−6x+2y=−14;−9x+3y=−21
Step: Solve−6x+2y=−14for x:
−6x+2y=−14
−6x+2y+−2y=−14+−2y(Add -2y to both sides)
−6x=−2y−14
−6x
−6
=
−2y−14
−6
(Divide both sides by -6)
x=
1
3
y+
7
3
Step: Substitute
1
3
y+
7
3
forxin−9x+3y=−21:
−9x+3y=−21
−9(
1
3
y+
7
3
)+3y=−21
−21=−21(Simplify both sides of the equation)
−21+21=−21+21(Add 21 to both sides)
0=0
Answer:
Infinitely many solutions.