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GenaCL600 [577]
3 years ago
7

Para el diseño de un tanque de tratamiento de agua se determina que su centro está ubicado en la posición (0;14) metros y está r

epresentado por la ecuación:
 
X^2+y^2-28y+180=0
 

Determine la medida del diámetro del tanque, en metros, que permitirá verificar que la construcción coincida con el diseño.
Mathematics
1 answer:
Andreas93 [3]3 years ago
7 0

Answer:

Diámetro = 8 metros

Step-by-step explanation:

La ecuación de la circunferencia esta en la forma general y para identificar su centro y su radio debemos llevarla a la forma canónica completando cuadrados:

x^{2} +y^{2} -28y + 180= 0

Solo necesitamos completar cuadrados en la variable y, sumando a ambos lados de la ecuación 196, que resulta de dividir 28 entre 2 y elevarlo al cuadrado

x^{2} +y^{2} -28y + 196 = -180 +196

Entonces obtenemos

x^{2} + (y-16)^{2} = 16

E identificamos que el radio del tanque es 4 metros y por tanto su perímetro es 8 metros

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joja [24]

a.

The y-coordinate of the vector with its terminal point in the second quadrant is 6.

The magnitude of the vector, r = √(x² + y²) where x = x-coorcinate of vector = -5 and y = y-coordinate of vector.

Since r = √61 and r = √(x² + y²)

Making y subject of the formula, we have

y = √(r² - x²)  

Substituting the values of the variables into the equation, we have

y = √((√61)² - (-5)²)  

y = √(61 - 25)  

y = ±√36

y = ±6

Since r is in the second quadrant, its y-coordinate is positive.

So, y = 6

So, the y-coordinate of the vector with its terminal point in the second quadrant is 6.

b.

The direction angle of the vector with its terminal point in the second quadrant is 130°

The direction angle of the vector is gotten from tanФ = y/x

Subsstituting x and y into the equation, we have

tanФ = y/x

tanФ = 6/-5

tanФ = -1.2

tan(180° - Ф) = 1.2

Taking inverse tan of both sides, we have

180° - Ф = tan⁻¹(1.2)

180° - Ф = 50.2°

Ф = 180° - 50.2°

Ф = 129.8°

Ф ≅ 130° to the neares whole number

The direction angle of the vector with its terminal point in the second quadrant is 130°.

Learn more about vectors here:

brainly.com/question/18478651

3 0
2 years ago
Find the range of f(x) = –x + 4 for the domain {–3, –2, –1, 1}.
marishachu [46]

Answer:

\boxed{ \{7, 6, 5, 3 \} }

Step-by-step explanation:

The domain is all possible values for x.

The range is all possible values for f(x) or y.

The domain given is {-3, -2, -1, 1}.

Plug x as {-3, -2, -1, 1} and find the f(x) or y values.

f(-3)=-(-3)+4=7\\f(-2)=-(-2)+4=6\\f(-1)=-(-1)+4=5\\f(1)=-(1)+4=3

The range is {7, 6, 5, 3}, when the domain is {-3, -2, -1, 1}.

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Answer:

Step-by-step explanation:

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Ivahew [28]

Answer:

Step-by-step explanation:

(a,9).......we dont know " a " (or x) but we do know y...it is 9

so sub in 9 for y and solve for x

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9 = 2x + 1

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Which shows the triangle when it is translated two units left
Naddika [18.5K]

Answer:

I believe it would be -3, 7?

Step-by-step explanation:

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Hope it helps?

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