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3 years ago

Triangle ABC is transformed to obtain triangle A′B′C′:

Mathematics

1 answer:

Firdavs [7]3 years ago

6 0

Answer:

Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 2. and then rotating it about the origin by 180 degrees

Step-by-step explanation:

All the coordinates of A'B'C' are -1/2 times those of ABC. The dilation factor is 1/2, and rotation by 180° is indicated.

A'(-1, -1) = (-1/2) × A(2, 2)

B'(-1, -5) = (-1/2) × B(2, 10)

C'(-4, -6) = (-1/2) × C(8, 12)

___

Rotation by 180° negates both coordinates. It is equivalent to reflection across the x-axis and reflection across the y-axis, in either order.

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Natalija [7]

Answer:

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Step-by-step explanation:

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3 years ago

Rico bought 3 adult tickets and 5 child tickets for a total of $50.

aliina [53]

Step-by-step explanation:

3x + 5y = 50

x + 5y = 31

use substitution

x = 31-5y

3(31-5y) +5y = 50

93 -15y + 5y = 50

93 - 10y = 50

--10y = -43

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3 years ago

Tyler’s family is using a shipping trailer that is 5 feet tall, 4 feet wide, and 12 feet long to load boxes of apples in. Each b

kogti [31]

Hello.

To get the volume 5184 in3 you can use the dimension 18in x 24in x 12in.

First, you should draw a picture of your shipping container. It is a rectangular prism that is 5 by 12 by 4.

Next, let's look at the boxes of apples that will go into the box. The volume has to be 5184 in^3. If we divide it by 12 and 12, the answer is 3. Therefore, we could make a box that is 1 foot by 1 foot by 3 feet.

Those boxes would be stack on the base without any left over space. Now, just figure out how many would go on the next rows. They would be able to stand up and down.

Have a nice day.

3 0

4 years ago

Read 2 more answers

(cotx+cscx)/(sinx+tanx)

Butoxors [25]

Answer: $\bold{\dfrac{cot(x)}{sin(x)}}$

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

$\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)$

$\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)$

$\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}$

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4 years ago

Help with questions 1-4

zalisa [80]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers