Perimeter of rectangle = length + length + width + width
To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14
Rectangle with perimeter 12
Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3
Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have
Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have
The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12
length = 4 and width = 2
length = 5 and width = 1
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Rectangle with perimeter of 14
Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14
Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14
Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14
We can have 3 different combinations of length and width
Hello there! 9+7=16. I hope this helps!
Multiply or divide the starting elements of a division problem (Divided and Divisor) by the same number, the quotient doesn't change. In other words, the answer is the same, and the remainder is multiplied or divided by that same number.
Answer:
and 
Step-by-step explanation:
At=As+Ar; A=b.h and 
, then: At=(x+120)x so
(x+120)x=4500, 
Applying cuadratic equation formula:
Answer:
1 and 1/6
Step-by-step explanation:
To rename a fraction you multiply both numbers by however many times the original denominator goes into the new one.
2 goes into 6 three times.
1 times 3 is 3
and 2 times 3 is 6
so 1/2=3/6
3 goes into 6 twice
2 times 2 is 4
and 2 times 3 is 6
so 2/3=4/6
to add fractions you add the numerators while keeping the denominators the same.
3+4=7 so:
3/6+4/6=7/6
6/6=1
so 7/6 contains 1 whole
once you take that out you have 1/6 left over
