Answer:
Rotation:
Step-by-step explanation:
Translation is usually movements like up, down, left, right.
Dilation is when one shape is bigger/smaller than the other, but still congruent.
Reflections are usually done over an axis (x or y), and don't change the degree at which a shape is turned. From looking at the triangles, you can see that one triangle was turned clockwise.
Answer:
0.053
Or
1 23/25
Step-by-step explanation:
Hope this helps! :D
Answer:
x = - 7, x = - 1
Step-by-step explanation:
To find the zeros let f(x) = 0 , that is
x² + 8x + 7 = 0
Consider the factors of the constant term (+ 7) which sum to give the coefficient of the x- term (+ 8)
The factors are + 7 and + 1 , since
7 × 1 = + 7 and 7 + 1 = + 8 , then
x² + 8x + 7 = 0
(x + 7)(x + 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 7 = 0 ⇒ x = - 7
x + 1 = 0 ⇒ x = - 1
Salutations!
<span>Are obtuse angles always, sometimes, or never equal to 180°?
Obtuse angles are angles </span>whose measure is greater than 90° and less than 180°. Its not always the case that an obtuse angle should be exact 180 °. So I reckon t would be sometimes, as its not always 180 °.
Hope I helped.
Answer:
Step-by-step explanation:
Whether we divide using long division or using synthetic division, the rule is the same: If, after division, there is no remainder (i. e., the remainder is zero), the divisor binomial is a factor or the associated root is indeed a root/zero/solution.
Divide 5x³+8x²-7x-6 by (x+2) using synthetic division. Use the divisor -2 (which comes from letting x+2 = 0):
--------------------------
-2 / 5 8 -7 -6
-10 4 6
------------------------------
5 -2 -3 0 Since the remainder here is 0, we know that
-2 is a root of 5x³+8x²-7x-6 and that (x+2) is
a factor of 5x³+8x²-7x-6.
Now check out the possibility that (x+1) is a factor of 5x^3 + 8x^2 - 7x - 6:
Use -1 as the divisor in synthetic division:
--------------------------
-1 / 5 8 -7 -6
-5 -3 10
------------------------------
5 3 -10 4
Since there is a non-zero remainder (4), we can conclude that (x + 1) is NOT a factor of the given polynomial expression.
