THREE Sweet potatoes cost 1.35 what is the unit price?

The width of the rectangle is 0.6 meters less than the length. The perimeter of a rectangle is 60.8 meters. Find the dimensions

Anvisha [2.4K]

Answer:

14+=+2L+%2B+2%28L-3%29 Simplify and solve for L

14+=+2L+%2B+2L+-+6 Combine like-terms.

14+=+4L-6 Add 6 to both sides.

20+=+4L Divide both sides by 4.

5+=+L The length is 5 meters.

W+=+L-3

W+=+5-3

W+=+2meters.

The width is 2 meters.

P+=+2L%2B2W

P+=+2%285%29%2B2%282%29

P+=+10%2B4

P+=+14meters.

Step-by-step explanation:

4 0

3 years ago

Lucy had $72 which is 9 times more than Xavier had

WINSTONCH [101]

Answer:

multiply 72 times 9

Step-by-step explanation: 648

6 0

3 years ago

Read 2 more answers

Use distributive property to rewrite 3×546

sergij07 [2.7K]

Answer:

1638

Step-by-step explanation:

3(500)+3(40)+3(6)=1500+120+18=1638

4 0

3 years ago

(x +y)^5<br> Complete the polynomial operation

Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

$\left(x+y\right)^5$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=x,\:\:b=y$

$=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$

so expanding summation

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

solving

$\frac{5!}{0!\left(5-0\right)!}x^5y^0$

$=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5$

$=1\cdot \:1\cdot \:x^5$

$=x^5$

also solving

$=\frac{5!}{1!\left(5-1\right)!}x^4y$

$=\frac{5}{1!}x^4y$

$=\frac{5x^4y}{1}$

$=5x^4y$

similarly, the result of the remaining terms can be solved such as

$\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2$

$\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3$

$\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4$

$\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5$

so substituting all the solved results in the expression

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

$=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

Therefore,

$\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

6 0

3 years ago

1. There is 1 /2cupcake left from Henry's birthday party. Henry and his friend want to share it equally. What fraction of a cupc

almond37 [142]

Answer:

1/4

Step-by-step explanation:

3 0

3 years ago