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sergij07 [2.7K]
3 years ago
14

When a binary tree is full to its next to last level and its leaves on the last level are filled from left to right the tree is

said to be
A. Ordered

B. Populated

C. Organized

D.complete
Computers and Technology
1 answer:
ikadub [295]3 years ago
8 0

Answer: D) Complete

Explanation:

A binary tree is said to be complete when, all the levels are completely fill except the last level. All the nodes leave in last level are all fill from left to right side in the binary tree.

If the current node in the binary tree indicated null value then, the tree are completely filled. If the last level is completely filled then,complete binary tree is known as perfect binary tree.

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Write a for loop that will print the values 1 to 20 while skipping the odd numbers (2,4,6,8,10,12,14,16,18,20):
DochEvi [55]

<u>Answer:</u>

<em>void main ( )  </em>

<em> {  </em>

<em> int counter;  </em>

<em>  cout<<""Even numbers between 1 to 20 are:""<<endl ;  </em>

<em> //Method 1 </em>

<em>  for (counter = 1; counter <= 20; counter++)  </em>

<em>  {  </em>

<em>    if ( counter%2 == 0)  </em>

<em>   {   </em>

<em>     cout<<counter<<""\t""<<endl ;  </em>

<em>   }  </em>

<em>  }  </em>

<em>//Method 2 – simplest one </em>

<em>for (counter = 2; counter <= 20;)  </em>

<em>  {  </em>

<em>     cout<<counter<<""\t""<<endl ;  </em>

<em>counter = counter + 2; </em>

<em>    </em>

<em>  } </em>

<em> </em>

<em>  return 0;  </em>

<em>} </em>

<u>Explanation:</u>

In this, Method 1 runs a for loop and check whether each number is divided by 2. If yes, then printed otherwise it is skipped.

In the second method, it runs for loop only for even numbers. <em>This is obtained by incrementing the counter by 2. </em>

6 0
3 years ago
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