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Ugo [173]
3 years ago
9

My mom hid my laptop and now I can't find it​

Computers and Technology
1 answer:
Svetach [21]3 years ago
3 0

Answer: did you look everywhere ask for it and be like mom i wont do (whatever you did) ever again so please give me a chance can i plsss!!!!!! have it back?

Explanation:

simple as that step by step

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Excel recognizes an entry as a value if it is a number or it begins with ____
Sedbober [7]
Excel recognizes an entry as a value if it is a number or it begins with symbol . As symbol in excel are considered the following signs: +, - , =, @, #, or $.
<span> Labels on the other hand are entries that contain text and numerical information not used in calculations.</span>
8 0
4 years ago
In this section, you will use a stack to implement a program that checks if a string is balanced. Use the skeleton code provided
zimovet [89]

Answer:

Check the explanation

Explanation:

#source code:

import sys

def is_balanced(input_string):

stack = []

for i in input_string:

if(i=="{"):

stack.append("{")

elif(i=="}"):

stack.pop()

if(len(stack)==0):

return True

else:

return False

if __name__ == '__main__':

try:

_input_string = sys.argv[1]

balanced = is_balanced(_input_string)

if balanced:

print("The string {} is balanced".format(_input_string))

else:

print("The string {} is not balanced".format(_input_string))

except:

print("String can't be empty")

Kindly check the attached image below to see the code screenshot and code output.

6 0
3 years ago
True or False:<br><br> You can convert your PowerPoint presentation in web pages.
jenyasd209 [6]

Answer:

true

Explanation:

4 0
3 years ago
Read 2 more answers
Plz I need the answer!!!:(
dimaraw [331]

Answer:

Procedural, Visual, Logic - Based

Explanation:

7 0
3 years ago
Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and s
S_A_V [24]

Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

int main() {

//  variable  

int num;

cout<<"Enter the number between 20 and 98: ";

// read number

cin >> num;

while(num<20||num>98)

{

   cout<<"Wrong input!!enter number between 20-98 only:";

   cin>>num;

}

cout<<"The output is: ";

while(num % 10 != num /10)

{

// print numbers.  

cout<<num<<" ";

// update num.

num--;

}

// display the number.

cout<<num<<endl;;

return 0;

}

Explanation:

Read a number from user and assign it to variable "num".Check if entered number  is in between 20-98 or not.If input number is less than 20 or greater than 98 then  ask again to enter a number between 20-98 until user enter a valid input.Then print  the countdown from input number till both the digit of number are same.

Output:

Enter the number between 20 and 98: 99                                                                                    

Wrong input!!enter number between 20-98 only:12                                                                            

Wrong input!!enter number between 20-98 only:93                                                                            

The output is: 93 92 91 90 89 88

Enter the number between 20 and 98: 77                                                                                    

The output is: 77

7 0
3 years ago
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