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4 years ago

9. Which property is illustrated by (6 x 5) x 4 =6 x (5 x 4)?

Mathematics

2 answers:

zaharov [31]4 years ago

5 0

Answer:

The property is Associative property of multiplication.

Step-by-step explanation:

Associative property

(a x b ) x c = (a x b ) x c

It is given that, (6 x 5) x 4 = 6 x (5 x 4)

To find the property

From the given statement (6 x 5) x 4 =6 x (5 x 4) we get, the corresponding property is associative property of multiplication.

To find LHS and RGHS

LHS = (6 x 5) x 4 = 30 x 4 = 120

RHS = 6 x (5 x 4) = 6 x 20 = 120

Advocard [28]4 years ago

4 0

For this case we have that by definition:

$(a * b) * c = a * (b * c)$

Indicates an example of the associative property of multiplication.

$(6 * 5) * 4 = 6 * (5 * 4)\\30 * 4 = 6 * 20\\120 = 120$

Similarly, we observe the associative property of multiplication

Answer:

associative property of multiplication

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4 years ago

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Given the functions f(n) = 500 and g(n) = (nine tenths)n − 1, combine them to create a geometric sequence, an, and solve for the

masya89 [10]

Answer:

$A(n) = 500 * (\frac{9}{10})^{n-1$

$A(11) = 174.34$

Step-by-step explanation:

Given

$f(n) = 500$

$g(n) = (\frac{9}{10})^{n-1$

Represent the combination of f(n) and g(n) with A(n)

So, we have:

$A(n) = f(n) * g(n)$

This gives:

$A(n) = 500 * (\frac{9}{10})^{n-1$

To calculate the 11th term, we make use of n = 11

$A(11) = 500 * (\frac{9}{10})^{11-1$

$A(11) = 500 * (\frac{9}{10})^{10$

This gives:

$A(11) = 500 * (0.9)^{10}$

$A(11) = 500 * 0.3486784401$

$A(11) = 174.33922005$

Approximate to 2 dp

$A(11) = 174.34$

3 0

3 years ago

Help, I’m stuck. Lol.

Darya [45]

Answer:

a. height = 12

b. area = 228

Step-by-step explanation:

a. To find the height, we can use the triangle formed by the side that measures 15, the side that measures 9. and the height. The hypotenuse of the triangle(the longest side opposite of the right angle), is 15. We can then use the Pythagorean Theorem, which states that $a^2+b^2=c^2$ , where c is the hypotenuse, and a and b are the two other sides. In this case, we need to find a leg of the triangle, not the hypotenuse. What do we do? We can first call the height a, and rearrange the Theorem into $c^2-b^2=a^2$ . $15^2=225, 9^2=81,$ and $225-81=\sqrt{144}$ =12. Therefore, the height of the parallelogram is $\boxed{12}$

b. To find the area of the parallelogram, we can use the area formula, which is Base*Height. The base is the flat side. We can find the base by adding 9+10=19, and $19\cdot12=\boxed{228}$