Use the traditional algorithm
1 answer:
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We can see this is a summation of multiples of 8 plus 1, which starts at 1.
This can be written in the following way:
Lets verify the summation expression by doing the sequence for the first 4 elements (hence
, as it starts from 0):
![\Sigma_{m=0}^{3}(8m+1)=[8(0)+1]+[8(1)+1]+[8(2)+1]+[8(3)+1]=](https://tex.z-dn.net/?f=%5CSigma_%7Bm%3D0%7D%5E%7B3%7D%288m%2B1%29%3D%5B8%280%29%2B1%5D%2B%5B8%281%29%2B1%5D%2B%5B8%282%29%2B1%5D%2B%5B8%283%29%2B1%5D%3D)
As you can see, the generalization is correct.
This can be written in the following way:
Lets verify the summation expression by doing the sequence for the first 4 elements (hence
As you can see, the generalization is correct.