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solniwko [45]
4 years ago
15

When coming yo decimals, do you move the decimal to fright when increasing or to the right when decreasing?

Mathematics
2 answers:
posledela4 years ago
8 0
You move to the right when you increase
Ne4ueva [31]4 years ago
5 0
Could you perhaps say that in a different way
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4+5(6p+2=24<br> ........
guajiro [1.7K]

Answer:

4+5\left(6p+2\right)=24

4+5\left(6p+2\right)-4=24-4

5\left(6p+2\right)=20

\frac{5\left(6p+2\right)}{5}=\frac{20}{5}

6p+2=4

6p+2-2=4-2

6p=2

p=\frac{1}{3}

7 0
3 years ago
Solve the equation<br> 1/10 (x+108)=-2(6-x)
pav-90 [236]

the answer is....x =12

5 0
4 years ago
Restrict the domain of the quadratic function and find its inverse. Confirm the inverse relationship using composition. f(x) = 0
ANTONII [103]

The given function is

f(x)= 0.2 x²

Since f(x) will be defined for all real values of x.

So, Domain of f(x) will be ( x| x is a real number.)→This is set builder notation.

Finding the inverse of f(x):

y = 0.2 x²

→ x²= 5 y

→x = \pm\sqrt{5 y}→ → Inverse of f(x)

Replacing x by y and y by x,we get inverse of the given function

y = \pm\sqrt{5 x}→ →Domain x ≥ 0, x∈[0,∞]

Graph of function and its inverse are shown below.

8 0
3 years ago
Read 2 more answers
The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)
Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}

Now, we have to find the quotient of the above expression.

So, here we go:

Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

Hence, the quotient is (x-2).


6 0
3 years ago
Read 2 more answers
A ′ B ′ C ′ triangle, A, prime, B, prime, C, prime is the image of △ A B C △ABCtriangle, A, B, C under a rotation about the orig
erma4kov [3.2K]

The angle of rotation of triangle ABC to A'B'C is 105°

<h3>How to illustrate the information?</h3>

It should be noted that the rotation from ABC to A'B'C is in a clockwise direction.

Point B is also on the x axis and point B' is in the second quadrant.

In this case, the angle that depicts the second quadrant is 105°.

In conclusion, the correct option is D.

The complete question is:

Triangle A’ B’ C’ is the image of A B C under a rotation about the origin, (0,0)

Determine the angle of rotation

A. -105 degrees

B. -75 degrees

C. 75 degrees

D. 105 degrees

Learn more about triangles on:

brainly.com/question/11485921

#SPJ1

8 0
2 years ago
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