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storchak [24]
2 years ago
13

Please help ill give whoever answers the best the brainliest answer :)

Mathematics
1 answer:
Sonbull [250]2 years ago
7 0

Answer: Quadratic

Step-by-step explanation:

I'm too lazy to explain. Trust me

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How do you add parentheses to 9 + 12 / 3 + 4 / 2 + 1 * 2 to make the answer 12? Please help quick.
morpeh [17]

Answer:

so the final answer is =17

Step-by-step explanation:

9+12/3=13+4/2=2+1*2=2 the answer is 13+2+2=17

4 0
2 years ago
HELP ASAP PLEASE!!!!!!
devlian [24]
A = (2+9)/2

a = 11/2

a = 5.5

__________________

b = (4+4)/2

b = 4

__________________

d = √(9-2)²+(4-4)²

d = √7²+0²

r = 3,5


____________________

(x-a)² + (y-b)² = r²

(x-5.5)² + (y-4)² = 3,5²

(x-5.5)² + (y-4)² = 12.25
5 0
3 years ago
Read 2 more answers
State the number of complex zeros, the possible number of real and imaginary zeros, and the possible rational zeros for each fun
ArbitrLikvidat [17]
Since the degree of this polynomial is 5, there will be 5 possible zeros. To find the possible rational 0s, use the rational root theorem (p/q). P is the last, non x value, which here it is the four on the end. The q is the leading coefficient, which is also q. Next, find all of the factors of q and p, which since they are both 4, are ±1, ±2, and ±4. Next do all possible values of p/q, which are ±1, ±2, ±4, ±1/2, and ±1/4. These are all your possible rational zeros. complex 0s only come in pairs, so the maximum there can be is 4 complex zeros, meaning there is at least one rational, real 0. (i graphed it it is -1/2, so all others must be rational or imaginary)
4 0
4 years ago
Help me with this one please
galben [10]

Answer:

I think the top and the two in the middle but I can't really see it's a blurry picture

7 0
4 years ago
Quick! Andrew has to play 15 games in a chess tournament. At some point during the tournament he has won half of the games he ha
nikklg [1K]

x - the number of the games he played

\dfrac{x}{2} - the number of the games he won

\dfrac{x}{3} - the number of the games he lost

x=\dfrac{x}{2}+\dfrac{x}{3}+2\Big|\cdot6\\6x=3x+2x+12\\x=12

15-12=3

<u>so, he has still 3 games to play</u>

3 0
3 years ago
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