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evablogger [386]
3 years ago
15

Essica and her sister, Nicole, need money for lunch. Jessica receives $50 and buys lunches at the high school for $2.50 each and

Nicole receives $40 and buy lunches at the elementary school for $1.50 each. How many lunches do they have to buy for the two girls to have the same amount of money in their account?
$50 - $1.50x = $40 - $2.50x
$50 - $1.50x = $40 - $2.50x

$50 - $2.50x = $40 - $1.50x
$50 - $2.50x = $40 - $1.50x

$50 + $1.50x = $40 + $2.50x
$50 + $1.50x = $40 + $2.50x

$50 + $2.50x = $40 + $1.50x
Mathematics
2 answers:
alisha [4.7K]3 years ago
4 0

Answer: $50 - $2.50x = $40 - $1.50x

Step-by-step explanation:

astraxan [27]3 years ago
3 0
I’m not sure about the answer, but my name is Jessica ✌
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A student receives his grade report from a local community college, but the GPA is smudged. He took the following classes: a 2 h
Olin [163]

Answer:

  • C. 3.0

Step-by-step explanation:

<u>Lets calculate the points:</u>

  • Art - 2 hrs - B (3)                ⇒ 2*3 = 6 points
  • History - 3 hrs - A (4)         ⇒ 3*4 = 12 points
  • Science - 4 hrs - C (2)       ⇒ 4*2 = 8 points
  • Math - 3 hrs - B (3)            ⇒ 3*3 = 9 points
  • Lab - 1 hr - A (4)                 ⇒ 1*4 = 4 points

<u>Totals</u>

  • Total hours = 13            
  • Total points = 39

<u>GPA = total points/ total hours</u>

  • GPA = 39/13 = 3.0

Correct option is C

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Which expression is equivalent to m-4/m+4 + (m+2) ?
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Answer:

C.

Step-by-step explanation:

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4 0
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A deli serves 6 kinds of lunch meat, 5 kinds of bread, and 4 types of sauce. How many sandwiches can be created with one type of
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A major credit card company has determined that customers charge between $100 and $1100 per month. If the monthly amount charged
Alexxx [7]

Answer:

a) E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

b) First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

c) P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

d) P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

Step-by-step explanation:

For this case we define the random variable X who represent the customers charge, and the distribution for X on this case is:

X \sim Unif (a= 100,  b=1100)

Part a

For this case the average is given by the expected value and we can use the following formula:

E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

Part b

First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

Part c

For this case we want to find the percent between 600 and 889, so we can use the cumulative distribution function given by:

F(x) = \frac{X -100}{1100-100}= \frac{x-100}{1000}, 100 \leq X \leq 1100

And we can find this probability:

P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

Part d

P(311 < X< 889) = P(X

And using the cdf we got:

P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

6 0
3 years ago
If f(x)=x/2-2and g(x)=2x^2+x-3 find (f+g) (x)
olya-2409 [2.1K]

Answer:

C   2x^2 + 3/2x -5

Step-by-step explanation:

f(x)=x/2-2

g(x)=2x^2+x-3

(f+g) (x)=x/2-2+2x^2+x-3

Combine like terms

           2x^2 + 3/2x -5

4 0
4 years ago
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