All categories

2 years ago

PLS HELP I WILL MARK BRAINLEST

Mathematics

1 answer:

Karo-lina-s [1.5K]2 years ago

7 0

Answer:

Angle G is 79 degrees

Step-by-step explanation:

They are in the same location on each triangle and have a congruent side.

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The future value of Elijah's certificate of deposit (CD), for the first five years, is represented by the sequence below. The ap

Citrus2011 [14]

The future value of Elijah's certificate of deposit (CD), for the first five years, is represented by the sequence below. The applied interest is compound interest.

$517.50, $535.61, $554.36, $573.76, $593.84, ..

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2 years ago

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How to solve h when equation is |3h+1|=7h

tatuchka [14]

Answer:

h= 1/4 is your answer.

Step-by-step explanation:

What you do is get h by itself.

|3h+1|=7h

-4h+1=0

-4h=-1

h=1/4

h= 1/4 is your answer.

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2 years ago

Maths trig functions please help

Nikitich [7]

1. According to the plots, the curves intersect when $x=90^\circ$ and $x=360^\circ$ .

We can confirm this algebraically.

$\sin(x) + 2 = -\cos(x) + 3$

$\sin(x) + \cos(x) = 1$

$\sqrt2 \sin\left(x + 45^\circ\right) = 1$

$\sin\left(x + 45^\circ\right) = \dfrac1{\sqrt2}$

$x + 45^\circ = \sin^{-1}\left(\dfrac1{\sqrt2}\right) + 360^\circ n \text{ or } x + 45^\circ = 180^\circ - \sin^{-1}\left(\dfrac1{\sqrt2}\right) + 360^\circ n$

(where $n$ is an integer)

$x + 45^\circ = 45^\circ + 360^\circ n \text{ or } x + 45^\circ = 135^\circ + 360^\circ n$

$x = 360^\circ n \text{ or } x = 90^\circ + 360^\circ n$

We get the two solutions we found in the interval [0°, 360°] with $n=1$ in the first case, and $n=0$ in the second case.

2. We have $\sin(x)=0$ when $x \in \{0^\circ, \pm 180^\circ, \pm360^\circ, \ldots\}$ . For the given plot domain [0°, 360°], this happens when $180^\circ < x < 360^\circ$ .

3. The domain for both equations is all real numbers in general, but considering the given plot, you could argue the domains would be [0°, 360°].

$\sin(x)$ is bounded between -1 and 1, so $\sin(x) + 2$ is bounded between -1 + 2 = 1 and 1 + 2 = 3, and its range is [1, 3].

Likewise, $-\cos(x)$ is bounded between -1 and 1, so that $-\cos(x)+3$ is bounded between -1 + 3 = 2 and 1 + 3 = 4, so its range would be [2, 4].

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1 year ago

How do I Simplify 8 3/4

Ainat [17]

Convert the mixed number 834834 into an improper fraction first by multiplying the denominator (44) by the whole number part (88) and add the numerator (33) to get the new numerator. Place the new numerator (3535) over the old denominator (44).354354The result can be shown in both exact and decimal forms.Exact Form:354354Decimal Form:8.758.75Mixed Number Form:834

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3 years ago

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A diameter of a circle has endpoints P(-10,-2) and Q(4,6).

Lesechka [4]

Check the picture below.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{-10}~,~\stackrel{y_1}{-2})\qquad Q(\stackrel{x_2}{4}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{4-10}{2}~~,~~\cfrac{6-2}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{4}{2} \right)\implies \stackrel{\textit{center}}{(-3~,~2)} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{\textit{center}}{(\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})}\qquad Q(\stackrel{x_2}{4}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[4-(-3)]^2+[6-2]^2}\implies r=\sqrt{(4+3)^2+(6-2)^2} \\\\\\ r=\sqrt{49+16}\implies r=\sqrt{65} \\\\[-0.35em] ~\dotfill$

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{2}{ k})\qquad \qquad radius=\stackrel{\sqrt{65}}{ r} \\[2em] [x-(-3)]^2+[y-2]^2=(\sqrt{65})^2\implies (x+3)^2+(y-2)^2=65$

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2 years ago