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Art [367]
3 years ago
9

Please help... I'm struggling

Mathematics
1 answer:
babunello [35]3 years ago
8 0

Answer:

c

Step-by-step explanation:

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Find the missing side length. and how do i set up to solve?
nikitadnepr [17]

Answer:

its 6 because the lines show they are parellel so it has to be equal to 18 and 12 plus 6 is 18

Step-by-step explanation:

6 0
3 years ago
June runs a little slower than Carlos. She ran .25 of a mile in 3 mins. How long will it take her to run a full mile
salantis [7]
12 min. derp, times 3 min, by 4 

8 0
3 years ago
Read 2 more answers
Let V be the volume of a right circular cone of height h=14 whose base is a circle of radius R=2. An illustration a right circul
Alla [95]

Answer:

The area of a horizontal cross section at a height is \pi\times(2-\dfrac{y}{7})^2

Step-by-step explanation:

Given that,

Height = 14 m

Radius = 2 m

Let V be the volume of a right circular cone

We need to calculate the value of R

Using given data

\dfrac{h}{r}=\dfrac{h-y}{R}

Put the value into the formula

\dfrac{14}{2}=\dfrac{14-y}{R}

7R=14-y

R=2-\dfrac{y}{7}

We need to calculate the area of a horizontal cross section at a height y

Using formula of area

A=\pi R^2

Put the value into the formula

A=\pi\times(2-\dfrac{y}{7})^2

Hence, The area of a horizontal cross section at a height is \pi\times(2-\dfrac{y}{7})^2

3 0
3 years ago
The scale on a map is 5.1 cm : 2 mi. Find the distance in miles between two cities that are 12 centimeters apart on the map. Rou
Lyrx [107]
Your answer is 4.7mi
3 0
3 years ago
Write the explicit formula that represents the geometric sequene -2,8,-32,128
Vladimir [108]
Well, is a geometric sequence, the first term's value is -2

to get the subsequent term's value, we'd multiply by "something" so-called the "common ratio"

well, if we simply just divide any of those values by the one before it, the quotient must be the "common ratio".

hmm say for exampl -32/8 = -4  <---- there's our common ratio

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=-2\\&#10;r=-4&#10;\end{cases}\implies a_n=-2 (-4)^{n-1}
4 0
3 years ago
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