Answer:
Step-by-step explanation:
Alright, lets get started.
Lets find slope for both bikes one by one
For bike 1 :
There are two points on the graph of Bike 1, these two points are (2,3) and (4,6)
So the slope for bike 1 is : 
So the slope for bike 1 is : 
So the slope for bike 1 is : 
For bike 2 :
There are two points on the graph of Bike 2, these two points are (4,5) and (8,10)
So the slope for bike 2 is : 
So the slope for bike 2 is : 
Hence Bike 1 will win the race as slope of line bike1 is greater than slope of line bike 2. So, answer is option D
Answer:
1. number of data values
2. sum of data values
Step-by-step explanation:
The equation is actually

. Free fall is always -16t^2 as the position function. We are looking for how long it takes the object to hit the ground. In other words, the height of an object is 0 when it is laying on the ground, so how long (t) did it take to get there? We will then set that position equal to 0 and solve for t.

. If we subtract 1437 from both sides and divide by -16, we have

. Taking the square root of both sides gives us, rounded to the nearest tenth, t = 9.5 or t=-9.5. The 2 things in math that will never EVER be negative are time and distance/length, so -9.5 is out. That means that it took just about 9.5 seconds for the object to fall to the ground from a height of 1437 feet when pulled on by the force of gravity.
You multiply 8x4=32 and then divide 32÷2= 16in²
The answer:
<span>the average rate of change for the first 50 seconds:
it is v= 100 m/ 50 s = 2 m/s
</span><span>Thomas speed is 2 m in each second for the first 50 seconds.
</span><span>The average rate of change for the 70 remaining seconds:
the time is between [70; 120]
so the distance is d= 200m - 40m= 160m
the average rate is
v= 160m / 70 s = 2 . 28m /s
</span>